Answer:
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Explanation:
Answer:
In engineering and materials science, a stress–strain curve for a material gives the relationship between stress and strain. It is obtained by gradually applying load to a test coupon and measuring the deformation, from which the stress and strain can be determined (see tensile testing).
Explanation:
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Using the knowledge of computational language in python it is possible to write a code that writes a list and defines the arrange.
<h3>Writing code in python:</h3>
<em>def isSorted(lyst):</em>
<em>if len(lyst) >= 0 and len(lyst) < 2:</em>
<em>return True</em>
<em>else:</em>
<em>for i in range(len(lyst)-1):</em>
<em>if lyst[i] > lyst[i+1]:</em>
<em>return False</em>
<em>return True</em>
<em>def main():</em>
<em>lyst = []</em>
<em>print(isSorted(lyst))</em>
<em>lyst = [1]</em>
<em>print(isSorted(lyst))</em>
<em>lyst = list(range(10))</em>
<em>print(isSorted(lyst))</em>
<em>lyst[9] = 3</em>
<em>print(isSorted(lyst))</em>
<em>main()</em>
See more about python at brainly.com/question/18502436
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Answer:
Resistor B
Explanation:
Since resistance is the opposition to the flow of current in a circuit,
first let assume the two resistors are connected in parallel to the voltage, recall that when connection is in parallel, the different amount of current pass through the resistors depending on the value with the small resistor having a lower resistance effect hence higher current will pass through
The energy dissipated in each resistor can be calculated as
.
from the formula we can conclude that the energy value will be higher for the resistor with small resistance value. hence more heating effect which will cause it to be warm.
Also when connected individually the current flow from the voltage source will pass through the resistor which when we calculate the energy dissipated, the resistor with smaller value will be higher because it will draw more current which will in turn lead to a heating effect and cause the resistor to be warm. Hence we can conclude that the resistance B has greatest resistance value.
Answer:
vehicle density = 28.205 veh/mile
flow rate = 0.909 veh/hr
Explanation:
given data
count n = 21
distance = 0.78 miles
speed = 52 mph
solution
we get here vehicle density that is express as
vehicle density = n ÷ distance ...............1
vehicle density = ( 21 + 1 ) ÷ 0.78
vehicle density k = 28.205 veh/mile
and
now we get here flow rate that is express as
flow rate = k × vs .................2
flow rate = 28.205 × ( 52 × 0.00062 ÷ 1m )
flow rate = 0.909 veh/hr