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Galina-37 [17]
3 years ago
8

What is the concentration of HNO3 if 5.00×10−2 mol are present in 905 mL of the solution?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

0.05525 M or 55.25 mM

Explanation:

Concentration = moles/volume

*Note that volume is expressed in L so you will need to convert mL > L here

C= \frac{n}{V}\\C= \frac{0.05}{0.905}\\C=0.05525

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An isotope of potassium with a half-life of roughly one billion years is often used in radioactive dating. This isotope decays t
melisa1 [442]

Answer : The chemical symbol for the element that results from this process is, (Ar) for argon.

Explanation :

Electron capture : In this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. Simply, a proton and an electron combines together to form a neutron. Mass number does not change in this process.

_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}

The equation for the given reaction is,

_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}

Thus, the chemical symbol for the element that results from this process is, argon (Ar).

7 0
4 years ago
Calculate the number of atoms of sodium in a 4.5-gram sample
allochka39001 [22]

Answer:

1.18×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms.

From the above concept, 1 mole of sodium also contains 6.02×10²³ atoms.

1 mole of sodium = 23 g.

Thus,

23 g of sodium contains 6.02×10²³ atoms.

Therefore, 4.5 g of sodium will contain = (4.5 × 6.02×10²³)/23 = 1.18×10²³ atoms.

From the above calculation,

4.5 g of sodium contains 1.18×10²³ atoms.

7 0
3 years ago
Carbon dioxide (CO2) is a gas at room temperature and pressure. However, carbon dioxide can be put under pressure to become a "s
Lunna [17]

Answer:

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

Explanation:

Step 1: Given data

The supercritical CO2 has a density of 0.469 g/cm³ (or 0.469 g/mL)

The sample hasa volume of 25.0 mL

Step 2: Calculating mass of the sample

The density is the mass per amount of volume

0.469g/cm³ = 0.469g/ml

The mass for a sample of 25.0 mL = 0.469g/mL * 25.0 mL = 11.725g ≈ 11.7g

The mass of this 25 mL supercritical CO2 sample has a mass of 11.7g

5 0
4 years ago
4. Describe the water conditions in the latitudes where coral reefs are found.<br> Help
Fofino [41]

Answer:

  • Most coral reefs lie between the latitudes of 30 degrees north and south where sea temperatures are warmest.
  • it is generally present in tropical and semi-tropical waters.
3 0
3 years ago
Help with this please
Len [333]

Answer:

12

Explanation:

There are 4 sulfur atoms in SO4

4×3=12

This means that it turns into 3×(SO4)

=3SO4

6 0
3 years ago
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