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Galina-37 [17]
3 years ago
8

What is the concentration of HNO3 if 5.00×10−2 mol are present in 905 mL of the solution?

Chemistry
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

0.05525 M or 55.25 mM

Explanation:

Concentration = moles/volume

*Note that volume is expressed in L so you will need to convert mL > L here

C= \frac{n}{V}\\C= \frac{0.05}{0.905}\\C=0.05525

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The density of water is 1.00 g/mL. If your swimming pool holds 208,000 gallons of water, what is the weight of the water in a fi
Natasha2012 [34]

Answer:

12.455≈12.5 tons

Explanation:

1 US gallon of water (gal) = 8.35 pounds of water (lb wt.)

so we divide 208,000 by 8.35 to covert to pounds

then divide the pounds by 2000 to convert to tons.

8 0
3 years ago
Excited lithium ions emit radiation at a wavelength of 670.8 nm in the visible range spectrum. Calculate the frequency of a phot
zzz [600]

Answer : The frequency of a photon of radiation is, 4.47\times 10^9s^{-1}

Explanation : Given,

Wavelength of the radiation = 670.8 nm

First we have to convert wavelength form 'nm' to 'm'.

Conversion used : (1nm=10^{-9}m)

So, the wavelength of the radiation = 670.8 nm = 670.8\times 10^{-9}m

Now we have to calculate the frequency of a photon of radiation.

Formula used : \nu =\frac{c}{\lambda}

where,

\nu = frequency of a photon of radiation

\lambda = wavelength of the radiation

c = speed of light = 3\times 10^8m/s

Now put all the given values in the above formula, we get the frequency of a photon of radiation.

\nu =\frac{3\times 10^8m/s}{670.8\times 10^{-9}m}

\nu =4.47\times 10^9s^{-1}

Therefore, the frequency of a photon of radiation is, 4.47\times 10^9s^{-1}

6 0
4 years ago
Read 2 more answers
Which of the following is the correct definition of density?
egoroff_w [7]

Answer:

3

Explanation:

The amount of mass per given vol

5 0
3 years ago
All atoms of the same element:
Aliun [14]

Answer:

have the same number of protons

Explanation:

The number of protons in an atom determine what element it is. The number of electrons and neutrons can vary from atom to atom of the element, as long as all the atoms have the same number of protons.

5 0
4 years ago
The atomic mass of element A is 35.45 amu. A 28.54 g sample of A combines with 85.42 g of another element B to form a compound A
vodka [1.7K]

The atomic mass of element B is 106.1 amu.

Given:

  • The atomic mass of element A is 35.45 amu.
  • A +B → AB
  • 28.54 g sample of A combines with 85.42 g of another element B

To find:

The atomic mass of element B.

Solution:

The mass of element A = 28.54 g

The atomic mass of element A = 35.45 amu = 35.45 g/mol

Moles of element A :

= \frac{28.54 g}{35.45 g/mol}=0.8051 mol

A +B → AB

According to reaction, one mole of A combines with 1 mole of B , then 0.8051 moles of A will combine with:

=\frac{1}{1}\times 0.8051 mol=0.8051 \text{ mol of B}

Moles of B element = 0.8051 mol

Mass of element B used = 85.42 g

The atomic mass of element B =M

0.8051 mol=\frac{85.42 g}{M}\\M=\frac{85.42 g}{0.8051 mol}=106.1 g/mol = 106.1 amu

The atomic mass of element B is 106.1 amu.

Learn more about moles of substance here:

brainly.com/question/2293005?referrer=searchResults

brainly.com/question/2293228?referrer=searchResults

3 0
3 years ago
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