Question

The atomic mass of element A is 35.45 amu. A 28.54 g sample of A combines with 85.42 g of another element B to form a compound AB Calculate the atomic mass of B. *

Answer 1

The atomic mass of element B is 106.1 amu.

Given:

• The atomic mass of element A is 35.45 amu.
• A +B → AB
• 28.54 g sample of A combines with 85.42 g of another element B

To find:

The atomic mass of element B.

Solution:

The mass of element A = 28.54 g

The atomic mass of element A = 35.45 amu = 35.45 g/mol

Moles of element A :

= $\frac{28.54 g}{35.45 g/mol}=0.8051 mol$

A +B → AB

According to reaction, one mole of A combines with 1 mole of B , then 0.8051 moles of A will combine with:

$=\frac{1}{1}\times 0.8051 mol=0.8051 \text{ mol of B}$

Moles of B element = 0.8051 mol

Mass of element B used = 85.42 g

The atomic mass of element B =M

$0.8051 mol=\frac{85.42 g}{M}\\M=\frac{85.42 g}{0.8051 mol}=106.1 g/mol = 106.1 amu$

The atomic mass of element B is 106.1 amu.

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