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USPshnik [31]
3 years ago
12

Inside a car that was at STP, a 1.33 L bottle warms up to 130 C. If the volume of the bottle remains constant, what is the press

ure, in atm, inside the hot water bottle?
Chemistry
1 answer:
fiasKO [112]3 years ago
7 0

Answer:

P_2=1.48atm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

\frac{P_2}{T_2} =\frac{P_1}{T_1\\ }

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

P_2 =\frac{P_1T_2}{T_1 }\\\\P_2 =\frac{1atm*403.15K}{273.15K}\\\\P_2=1.48atm

Regards!

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There are (how many?) significant figures in: 0.0050110400
DanielleElmas [232]
I want to say 8 but i'm not sure. I just did a lesson on this and my notes say it could be 8 but then again I'm not sure. 
5 0
3 years ago
Measuring how quickly a reactant disappears is one way to measure the ______________of the reaction
LUCKY_DIMON [66]

Explanation:

More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.

Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.

5 0
4 years ago
Read 2 more answers
A chemical company makes ammonia by reacting nitrogen with hydrogen. The company needs to make 70 batches of ammonia for a clien
RSB [31]

Answer:- No, the company would not be able to full fill the order.

Solution:- The balanced equation for the formation of ammonia by the reaction of hydrogen with nitrogen is:

3H_2+N_2\rightarrow 2NH_3

We have been given with 22000 grams of nitrogen and 1000 grams of hydrogen. Let's convert grams of each to moles:

moles of nitrogen = 22000g N_2(\frac{1mol}{28g})

moles of nitrogen = 785.71 mol

moles of hydrogen = 1000g H_2(\frac{1mol}{2g})

moles of hydrogen = 500 mol

From balanced equation 3 moles of hydrogen react with 1 mol of nitrogen. Let's calculate how many moles of nitrogen would react with 500 mol of hydrogen:

500mol H_2(\frac{1mol N_2}{3mol H_2})

= 166.67 mol N_2

166.67 moles of nitrogen are required and 785.71 moles of it are available. It means nitrogen is in excess and hydrogen is limiting. Product yield depends on limiting reactant. So, let's calculate the amount of ammonia formed from moles of hydrogen as:

500mol H_2(\frac{2mol NH_3}{3mol H_2})(\frac{17g NH_3}{1mol NH_3})

= 5666.67g of ammonia

let's convert the grams of ammonia to number of batches as:

5666.67g NH_3(\frac{1 batch}{175g NH_3})

= 32 batches

Company needs to make 70 batches of ammonia but from given amounts of hydrogen and nitrogen only 32 batches could be made. It means the company would not be able to full fill the order.

5 0
3 years ago
What is the answer to this question
Stels [109]

Answer:

38 kg/m³

0.038 g/mL

Explanation:

Volume of a cube is the side length cubed.

V = s³

Given s = 0.65 m:

V = (0.65 m)³

V ≈ 0.275 m³

The mass is 10.5 kg.  The density is the mass divided by volume:

ρ = (10.5 kg) / (0.275 m³)

ρ ≈ 38 kg/m³

Or:

ρ ≈ 0.038 g/mL

4 0
3 years ago
Does anyone know this??
soldier1979 [14.2K]

Answer:

9 moles of N2

Explanation:

Well first you balance the equation which would be N2+3 H2>2 NH3. But you need 18 miles of NH3 so you would just replace the 2 moles of NH3 with 18 and balance the rest of the equation from there. And you would get 9 N2 + 27 H2>18 NH3

3 0
3 years ago
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