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Zolol [24]
3 years ago
13

Only some shortwave radiation from the Sun reaches Earth’s surface. What is the leading cause of this radiation loss? Only some

shortwave radiation from the Sun reaches Earth’s surface. What is the leading cause of this radiation loss? absorption by greenhouse gases absorption by ozone scattering by air reflection by clouds absorption by clouds
Physics
1 answer:
anastassius [24]3 years ago
4 0

Answer: Reflection by clouds

Explanation:

Only some shortwave radiation from the sun reaches the Earth's surface because solar radiation is being reflected by  thick clouds and thin clouds transmit the  solar radiation.

About 31 % of solar radiation is reflected by clouds. The tiny water particle scatters 20-90 % of incoming sunlight giving them a bright white appearance.

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Two satellites are in circular orbits around Earth. Satellite A has speed vA. Satellite B has an orbital radius nine times that
Pani-rosa [81]

Answer:

option B

Explanation:

given,

Satellite B has an orbital radius nine times that of satellite A.

R' = 9 R

now, orbital velocity of the satellite A

........(1)

now, orbital velocity of satellite B

from equation 1

hence, the correct answer is option B

8 0
3 years ago
If you tried to use a diverging lens as a magnifier by placing the object at the focal point, what type of image would be produc
gladu [14]

Answer:

Upright and smaller than the object

Explanation:

Diverging lens as the name suggests that the rays diverge after the refraction and do not meet in reality. A concave lens is called diverging lens. When there is refraction of light through a concave lens then the light bends away from the principal axis and hence never meet in reality but on tracing the rays backwards the rays appear to meet leading to the formation of a virtual image, which is erect and smaller than the object for an object placed at the focus of the lens.

Similar image is formed for any case when the object is between optical center and infinity.

7 0
4 years ago
(a) What magnitude point charge creates a 10,000 N/C electric field at a distance of 0.250 m? (b) How large is the field at 10.0
Sergio039 [100]
<h2>Answer:</h2>

(a) 6.95 x 10⁻⁸ C

(b) 6.25N/C

<h2>Explanation:</h2>

The electric field (E) on a point charge, Q, is given by;

E = k x Q / r²              ---------------(i)

Where;

k = constant = 8.99 x 10⁹ N m²/C²

r = distance of the charge from a reference point.

Given from the question;

E = 10000N/C

r = 0.250m

Substitute these values into equation(i) as follows;

10000 = 8.99 x 10⁹ x Q / (0.25)²

10000 = 8.99 x 10⁹ x Q / (0.0625)

10000 = 143.84 x 10⁹ x Q

Solve for Q;

Q = 10000/(143.84 x 10⁹)

Q = 0.00695 x 10⁻⁵C

Q = 6.95 x 10⁻⁸ C

The magnitude of the charge is 6.95 x 10⁻⁸ C

(b) To get how large the field (E) will be at r = 10.0m, substitute these values including Q = 6.95 x 10⁻⁸ C into equation (i) as follows;

E = k x Q / r²

E = 8.99 x 10⁹ x 6.95 x 10⁻⁸ / 10²

E = 8.99 x 10⁹ x 6.95 x 10⁻⁸ / 100

E = 6.25N/C

Therefore, at 10.0m, the electric field will be just 6.25N/C

3 0
3 years ago
Which statement accurately describes the motion of the objects in the ticker tape above?
Fynjy0 [20]

Answer: "One object speeds up before it slows to a stop "

(the top one)

Explanation:

Ok, first a little recall on how to read this type of graph.

If the points are far apart, the object is moving fast.

If the points are close together, the object is moving slow.

If the distance between the points changes then the velocity of the object changes, which means that the object is accelerated.

If we have a lot of points clustered in one location, then the object is not moving.

We can see:

The top object starts slow, then it increments the speed, then it slows down again, and then it comes to stop.

The bottom object starts fast, and it slows down.

then:

"One object speeds up before it slows to a stop "

This describes the motion of the top object, this is the only correct option that describes one of the graphs.

5 0
3 years ago
How much work is done if a 4500 N piano is lifted 10 m?
AveGali [126]

Answer:

45000 J

Explanation: multiply the 4500 N by the 10 m

6 0
3 years ago
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