Answer:
I have solved the problem below. I hope it will let you clear the concept.
For any inquiries ask me in the comments.
Explanation:
Answer:
nmuda mudaf A certain vehicle loses 3.5% of its value each year. If the vehicle has an initial value of $11,168, construct a model that represents the value of the vehicle after a certain number of years. Use your model to compute the value of the vehicle at the end of 6 years.
Explanation:
Well you could always do what Hispanics do and repeat the question 2-3 times while yelling till they finally answer
Answer / Explanation:
Regarding α and β Particles in Windowless Counter, the range of α particles is lower than β particles. Alpha particles typically have range less than the dimensions of the gas chamber so that proportional counters are able to easily record. Hence, with almost 100% efficiency, each particle which enters the so called active volume.
Then, since the pulse height spectra depends on the number of ion pairs which have formed, an aplha particle with higher energy creates more ion pairs in the chamber. However, beta particle range usually exceeds the dimensions of the chamber and therefore most of the betas hit the walls where they deposit energy. Then, fewer ion pairs are formed because very few β’s give their energy to the bulk gas.
Question
The mean weight of a breed of yearling cattle is 1187 pounds. Suppose that weights of all such animals can be described by the Normal model N(1187,78).
a) How many standard deviations from the mean would a steer weighing 1000 pounds be?
b) Which would be more unusual, a steer weighing 1000 pounds, or one weighing 1250 pounds?
Answer:
a. z = -2.40
A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.
b. z = 0.81
1000 is more unusual because its contained on the extreme end from the mean
Explanation:
a.
Let weight (in pounds) of the cattle be denoted by letter x:
z = (x - u)/ σ
Where u = mean and σ = standard deviation
u = 1187
σ = 78
x = 1000
Use z score formula to standardize the value of x:
z = (1000 - 1187)/78
z = -187/78
z = -2.397436
z = -2.40 ------_ Approximated
A sleet weighing 1,000 pounds is 2.40 standard deviations below the mean.
b.
x= 1250
z= (1250 - 1187)/78
z = 63/78
z = 0.807692
z = 0.81 --------- Approximated
1000 is more unusual because its contained on the extreme end from the mean
