1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
3 years ago
15

Find the force of gravity between a cubic meter of water (1000kg) and the Sun. The Sun's mass is 1.99 x10^30 kg and is 1.50 x10^

11 m away.
A) 17.0 N
B) 5.90 N
C) 2.0 N
D) 47.20 N
Physics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

F = 5.9 N

Explanation:

Given that,

Mass of water, m₁ = 1000 kg

Mass of the Sun, m_2=1.99\times 10^{30}\ kg

Distance between two bodies, r=1.5\times 10^{11}\ m

We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N

or

F = 5.9 N

Hence, the correct option is (b).

You might be interested in
Mester Exam 1 11 of 35
frez [133]
Please show picture of diagrams
8 0
3 years ago
The correct sequence of layers of the atmosphere from innermost to outermost is
serious [3.7K]
Troposphere, stratosphere, mesosphere, thermosphere, exosphere
4 0
3 years ago
We can model a pine tree in the forest as having a compact canopy at the top of a relatively bare trunk. Wind blowing on the top
frez [133]

We need to consider for this exercise the concept Drag Force and Torque. The equation of Drag force is

F_D = c_D A \frac{\rho V^2}{2}

Where,

F_D = Drag Force

c_D = Drag coefficient

A = Area

\rho= Density

V = Velocity

Our values are given by,

c_D = 0.5 (That is proper of a cone-shape)

A = 9m^2

\rho = 1.2Kg/m^3

V = 6.5m/s

Part A ) Replacing our values,

F_D = 0.5*9*\frac{1.2*6.5^2}{2}

F_D = 114.075N

Part B ) To find the torque we apply the equation as follow,

\tau = F*d

\tau = (114.075N)(7)

\tau = 798.525N.m

3 0
3 years ago
A 1.00-kg object is attached by a thread of negligible mass, which passes over a pulley of negligible mass, to a 2.00-kg object.
Anna [14]

Answer:

a = 3.27 m/s²

v = 2.56 m/s

Explanation:

given,

mass A = 1 kg

mass B = 2 kg

vertical distance between them = 1 m

F_d = mg

F_d = 2 \times 9.8

F_d = 19.6\ N

F_u = mg

F_u = 1 \times 9.8

F_u = 9.8\ N

F_{net} = 19.6 - 9.8

F_{net}=9.8\ N

F = (m_1+m_2)a

9.8 = (2+1)a

a = 3.27 m/s²

The speed of the system at that moment is:

v² = u² + 2×a×s

v² = 0² + 2× 3.27 × 1

v ² = 6.54

v = 2.56 m/s

3 0
3 years ago
A student pushes on a crate with a force of 100 Newtons directed to the right.
romanna [79]

Answer:

100N

Explanation:

Newton's third law of motion

For every action, there is an equal and opposite reaction.

Therefore 100N of force is exerted by the crate on student as a reaction to his action

6 0
3 years ago
Other questions:
  • The earth pulls on the apple, and the apple pulls on the earth. This idea is represented by Newton's ___ Law of Motion.
    10·1 answer
  • Real gases are those that :
    5·1 answer
  • Some kids are playing dodgeball, in which they throw squishy balls at each other while trying to avoid being hit themselves. Ass
    8·1 answer
  • According to freud what part of the mind is concerned with morals and ethics
    6·1 answer
  • How long does it take to freeze ice cubes?
    5·1 answer
  • Radio waves coming from a radio station are tuned into by a student in class. What form of energy transfer does the radio statio
    15·1 answer
  • Write the importance of international bureau of weights and measurement.​
    15·1 answer
  • The energy required to dissociate KF into neutral atoms is 498 kJ/mol. Given that the first ionization energy for K is 418 kJ/mo
    13·1 answer
  • Click all that are examples of Kinetic Energy
    13·1 answer
  • The object was thrown vertically upwards at a speed of 30 m / s. How high does the body go?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!