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mars1129 [50]
3 years ago
15

Find the force of gravity between a cubic meter of water (1000kg) and the Sun. The Sun's mass is 1.99 x10^30 kg and is 1.50 x10^

11 m away.
A) 17.0 N
B) 5.90 N
C) 2.0 N
D) 47.20 N
Physics
1 answer:
alisha [4.7K]3 years ago
5 0

Answer:

F = 5.9 N

Explanation:

Given that,

Mass of water, m₁ = 1000 kg

Mass of the Sun, m_2=1.99\times 10^{30}\ kg

Distance between two bodies, r=1.5\times 10^{11}\ m

We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N

or

F = 5.9 N

Hence, the correct option is (b).

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A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
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Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

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now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

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v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

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so we will have

T = 29.6 N

5 0
4 years ago
If the volume of one drop is 0.031 mL according to Stu Dent’s measurement, approximately what volume would 22 drops be? Answer w
olasank [31]

Answer:

Volume of 22 drop will be 0.68 ml

Explanation:

We have given volume of one drop = 0.031 ml

We know that 1 liter = 1000 ml

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So 0.031 ml will be equal to 0.031\times 10^{-3}L

We have to find the volume of 22 drop

For finding volume of 22 drop we have to multiply volume of one drop by 22

So volume of 22 drop will be =22\times 0.031\times 10^{-3}=0.682\times 10^{-3}L=0.68mL

So volume of 22 drop will be 0.68 ml

7 0
4 years ago
A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
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initial velocity of the car given as

v_i = 0

final velocity is given as

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as we know that

1 km/h = 0.277 m/s

now we can convert final speed into m/s

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a = \frac{30 - 0}{10}

a = 3 m/s^2

so the acceleration of the car is 3 m/s^2

7 0
3 years ago
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