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ludmilkaskok [199]
3 years ago
7

Mester Exam 1 11 of 35

Physics
1 answer:
frez [133]3 years ago
8 0
Please show picture of diagrams
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How fast (in rpm) must a centrifuge rotate if a particle 7.50 cm from the axis of rotation is to experience an acceleration of 1
Andreas93 [3]

Explanation:

Below is an attachment containing the solution.

7 0
3 years ago
A ladybug sits 10.8 cm from the center of a beatles music album spinning at 33.33 rpm. What is the maximum velocity (in m/s) of
snow_lady [41]

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The maximum velocity is 0.377 m/s

Explanation:

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7 0
3 years ago
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the distance a spring will stretch varies directly with how much weight is attached to the spring. If a spring stretches 11 inch
Paha777 [63]
Direct variation involves ration and proportions, so 

you need to set up the proportion:

<span>11 / 75 = x / 65
 
Cross multiplying:

75x = 11*65

x = (11*65)/75

Solving, we get x = 9.533, </span>

<span>which rounds off to 9.5

Therefore, the spring will stretch up to 9.5 inches with 65 attached.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

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4 0
3 years ago
The amount of matter in an object
Mnenie [13.5K]
Alot? You didn’t show me any work to solve
6 0
3 years ago
Calculate the highest frequency X-rays produced by 8.00 · 104 eV electrons. _____ Hz
lys-0071 [83]
When an electron stops, it emits a photon with energy equal to the kinetic energy lost by the electron:
E=\Delta K
The energy of the photon is E=hf where h=6.63 \cdot 10^{-34} Js is the Planck constant and f is the frequency. Therefore, the maximum frequency of the emitted photon occurs when the loss of kinetic energy is maximum.

The maximum loss of kinetic energy of the electron occurs when the electron stops completely, so it loses all its energy:
\Delta K = 8\cdot 10^4 eV
Keeping in mind that 1 eV=1.6 \cdot 10^{-19}J, we have
\Delta K = 8 \cdot 10^4 eV \cdot 1.6 \cdot 10^{-19}J/eV = 1.28 \cdot 10^{-14}J

And so, this corresponds to the energy of the emitted photon, E. Therefore, we can find the maximum frequency of the emitted photon:
f= \frac{E}{h} = \frac{1.28 \cdot 10^{-14}J}{6.63 \cdot 10^{-34}Js}=1.93 \cdot 10^{19}Hz
5 0
3 years ago
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