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3 years ago

When 20 grams of KCIO3, is dissolved in 100 grams of water, the solution can be

Chemistry

1 answer:

tia_tia [17]3 years ago

6 0

Answer:

b. unsaturated .

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the definition of each type of solution:

- Supersaturated solution: comprises a large amount of solute at a temperature at which it will be able to crystalize upon standing.

- Unsaturated solution: is a solution in which a solvent is able to dissolve any more solute at a given temperature.

- Saturated solution can be defined as a solution in which a solvent is not capable of dissolving any more solute at a given temperature.

In such a way, since 20 grams of the solute are less than the solubility, we infer this is b. unsaturated, as 33.3 grams of solute can be further added to the 100 grams of water.

Regards!

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Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

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Thus , it is not acceptable.

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3 years ago

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Answer:

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