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Lerok [7]
3 years ago
13

When 20 grams of KCIO3, is dissolved in 100 grams of water, the solution can be

Chemistry
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

b. unsaturated .

Explanation:

Hello there!

In this case, according to the given information, it turns out necessary for us to bear to mind the definition of each type of solution:

- Supersaturated solution: comprises a large amount of solute at a temperature at which it will be able to crystalize upon standing.

- Unsaturated solution: is a solution in which a solvent is able to dissolve any more solute at a given temperature.

- Saturated solution can be defined as a solution in which a solvent is not capable of dissolving any more solute at a given temperature.

In such a way, since 20 grams of the solute are less than the solubility, we infer this is b. unsaturated, as 33.3 grams of solute can be further added to the 100 grams of water.

Regards!

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What amount of heat is removed to lower the temperature of 80 grams of water from 75º C to 45º C? The specific heat of liquid wa
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Answer:The correct answer option A.

Explanation:

Q= m\times c\times \Delta T

Q= heat removed from the water

m= mass of the water = 80 grams

c = heat capacity of water= 4.18 J/g°C      

\Delta T={\text{Change in temperature}}=45^oC-75^oC=-30^oC  

Q=80g\times 4.18J/g^oC\times(-30^oC)

Q = -10,032 joules \approx -10,000 Joules

Negative sign indicates that heat was removed from the water.

Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.

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On the basis of your knowledge of the reaction of halogens with alkanes, decide which product you would not expect to be formed
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Answer:

On the basis of your knowledge of the reaction of halogens with alkanes, decide which product you would not expect to be formed in even small quantities in the bromination of ethane?

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C) CH3CHBr2

D) CH3CH2CH2CH3

E) BrCH2CH2CH2CH2Br

Explanation:

The reaction of ethane with bromine in presence of UV light forms mono substituted ethane at all primary and secondary carbons.

This is an example of free radical substitution.

The structure of ethane and its bromination is shown below:

Among the given options that which is not possible to form is option B) that is CH3CH2CH2Br(propyl bromide).

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5 x 2 = 10

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