Using the periodic table, choose the more reactive nonmetal. Te or O
2 answers:
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Answer:
The correct option is e.
Explanation:
p-value is the probability value for a given statistical model, the probability that, when the null hypothesis is true.
For two two samples the formula of test statistics is
where,
is sample mean
is population mean.
is standard deviation.
n is sample size.
Variance is the square of standard deviation.
It means variance, mean, numbers of samples is used in calculation of p-value.
Degree of freedom define the shape of the t-distribution that your t-test uses to calculate the p-value.
p-value of a statistical test depends on all of the following, except median.
Therefore the correct option is e.
The hybrid orbital of this molecule is . Hence, option C is correct.
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound, a hybrid orbital makes I-O bonds. Due to
hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of
the ion is pyramidal.
The hybrid orbital of this molecule is . Hence, option C is correct.
Learn more about hybridisation here:
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Answer:- 0.273 kg
Solution:- A double replacement reaction takes place. The balanced equation is:
We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.
= 63.8 g aluminum nitrate
From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.
We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.
=
sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate and then the grams are converted to kg.
= 0.273 kg
So, 0.273 kg of 35% m/m sodium chlorate solution are required.