Calculate the number of C atoms in 0.190 mole C6H14O. can anyone help me on this one?
1 answer:
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Answer: The value of for the half-cell reaction is 0.222 V.
Explanation:
Equation for solubility equilibrium is as follows.
Its solubility product will be as follows.
Cell reaction for this equation is as follows.
Reduction half-reaction: ,
Oxidation half-reaction: ,
= ?
Cell reaction:
So, for this cell reaction the number of moles of electrons transferred are n = 1.
Solubility product,
=
Therefore, according to the Nernst equation
At equilibrium, = 0.00 V
Putting the given values into the above formula as follows.
=
= 0.577 V
Hence, we will calculate the standard cell potential as follows.
= 0.222 V
Thus, we can conclude that value of for the half-cell reaction is 0.222 V.