Let the slower train's velocity be x-21
Let the faster train's velocity be x
We know that the approach speed is the sum of both speeds, so x+x -21= 2x-21.
The approach rate is given by Distance/time = 471/3 = 157mpH
x+x-21=157
2x=157+21
2x=178
x=89mph
The slower train is travelling 89-21 = 68mph
The faster train is travelling 89mph.
Answer:
Step-by-step explanation:
When the exponent is attached to the trig function like that, its essentially the same thing as taking the entire function to that power.
tan^2(x) = (tanx)^2
Answer:
114
Step-by-step explanation:
