Answer:
y= -x+7, b= sqrt(2P/a), c=3P^2-b
Step-by-step explanation:
First, make a table regarding both of the equations. You will eventually find out that both lines intersect at the point (2, 5) after you find the points on the table. From there, subtract x from both sides in the equation x + y = 2. You will get y = -x + 2. Since they said the line was parallel, find a line that has the slope of negative one. Since we know that this line intersects the point in which the first two lines intersect, we know that the y-intercept will be 7. The equation of the line would be y=-x+7.
Multiply both sides by 2. Then, divide both sides by a to get b^2=(2P/a). Take the square root to get the value of b, which is sqrt(2P/a).
Square both sides of the equation to get P^2=(b+c)/3. Cross multiply to get 3P^2=b+c. Subtract b from both sides to get c=3P^2-b.
Hello!
The slope intercept form is y=mx+b, where m is the slope and b is the y-intercept.
First, let's find the y-intercept. This is where the line hits the y-axis. Therefore, it hits at 4 on the y-axis, so our y-intercept is 4.
To find the slope, let's find 2 points on our line. Let's use (0,4) and (2,5). We divide the difference in the y-values by the difference in the x-values as shown below.
Therefore, our slope is 2.
Now we plug these values into our equation.
y=2x+4
I hope this helps!
Answer: Lol your in collage I don't believe it anyway the answer is 20 min on the dot
