Answer:
Step-by-step explanation:
1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min
By comparing P(0 ≤ Z ≤ 30)
P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)
Using Table
P(0 ≤ Z ≤ 1) = 0.3413
P(Z > 1) = (0.5 - 0.3413) = 0.1537
∴ P(Z > 45) = 0.1537
2) By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)
P(Z ≤ 15 - 30/15) = P(Z ≤ -1)
Using Table
P(-1 ≤ Z ≤ 0) = 0.3413
P(Z < 1) = (0.5 - 0.3413) = 0.1587
∴ P(Z < 15) = 0.1587
3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)
P(Z ≤ 60 - 30/15) = P(Z ≤ 2)
Using Table
P(0 ≤ Z ≤ 1) = 0.4772
P(Z > 1) = (0.5 - 0.4772) = 0.0228
∴ P(Z > 60) = 0.0228
68-33 blockers ?????????????????????????????????????????!?!!
Answer:
One solution
Step-by-step explanation:
y = 2x – 5. –8x – 4y = –20. one solution: (–2.5, 0)
78.5/100 as a decimal is just 0.78.5 and as a percent it is 78.5 %
Answer:
The most absolute error is 12
Step-by-step explanation:
The formula for absolute error is given by the following relation;
Absolute error, Δx = Value measured, x₀ - Exact (actual) value, x
Δx = x₀ - x
Since the actual count is between 77 and 89, the maximum absolute error will be where the actual value = 77 and the measured value = 89 and vice versa, giving an absolute error of 89 -77 = 12.
The most absolute error = 12.
