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Simora [160]
2 years ago
5

Calculate the percent dissociation of crotonic acid (C,H,CO,H) in a 0.63 mM aqueous solution of the stuff.

Chemistry
1 answer:
Sauron [17]2 years ago
5 0

Answer:

16%

Explanation:

Crotonic acid : C₃H₅CO₂H

C₃H₅CO₂H  ⇄ C₃H₅CO₂⁻ +  H⁺

   C                      O                O

where : C = C ( 1 - ∝ ) ,   O = C∝

also:  Ka = C∝² / ( 1 - ∝ )  ---- ( 1 )

<em>From Alexa data resource : </em>

Pka = 4.69 ,  [  Ka = 2.04 * 10^-5 = C∝² / ( 1 - ∝ ) ]

back to equation 1

2.04 * 10^-5 = [ ( 0.63 * 10^-3 ) * ∝² / ( 1 - ∝ ) ]  ----- ( 2 )

∴ ∝² / ( 1 - ∝ ) = 3.24 * 10⁻²

Resolving equation above

∝ = 0.1645 =  16.45%

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3 years ago
Which of the following sets of elements could replace the generic "X" symbol with their own to produce a valid dot notation for
inessss [21]

Symbol  "X" represents Nitrogen, phosphorus, and arsenic.as they have five valence electrons in their valance shell.

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6 0
2 years ago
5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. Identify the group 2 metal
andrey2020 [161]

5.00 moles of a binary, group 2 oxide are found to have a mass of 521 g. The group 2 metal is Strontium.

According to question 5 moles of binary group 2 metal oxide mass =521  g

So, 1-mole metal oxide mass will be =521 / 5=104.2 g

Now, as metal oxide is group 2 oxide so metal: oxygen =1: 1

So the mass of metal is =104.2-16=88.2 gm (as the atomic mass of oxygen is 16 g

Therefore, the metal is Strontium(Sr) whose atomic mass is 87.62 g which is nearly 88.2 gm

So, the formula of metal oxide is SrO

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4 0
1 year ago
How much energy is needed when 1.27 moles of sulfur reacts with excess
pav-90 [236]

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6 0
3 years ago
A certain organ pipe, open at both ends, produces a fundamental frequency of 272 HzHz in air. Part A If the pipe is filled with
vladimir2022 [97]

Answer:

fundamental frequency in helium = 729.8 Hz

Explanation:

Fundamental frequency of an ope tube/pipe = v/2L

where v is velocity of sound in air = 340 m/s; λ is wave length of wave = 2L ; L  is length of  the pipe

To find the length of the pipe,

frequency  = velocity of sound / 2L

272 = 340 / 2 L

L = 0.625 m

If the pipe is filled with helium at the same temperature, the velocity of sound will change as well as the frequency of note produced since velocity is directly proportional to frequency of sound.

Also, the velocity of sound is inversely proportional to  square root of molar mass of gas; v ∝ 1/√m

v₁/v₂ = √m₂/m₁

v₁ = velocity of sound in air, v₂ = velocity of sound in helium, m₁ = molar mass of air, m₂ = molar mass of helium

340 / v = √4 / 28.8

v₂ = 340 / 0. 3727

v₂  =  912.26  m /s  

fundamental frequency in helium  = v₂ / 2L

fundamental frequency in helium = 912.26 / (2 x 0.625)

fundamental frequency in helium = 729.8 Hz

7 0
2 years ago
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