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Ksenya-84 [330]
3 years ago
15

Which one of the following equations is properly balanced? a. CH 3CHO + 3O 2 → 2CO 2 + 2H 2O b. NH 4NO 3 → 2H 2O + N 2 c. Na 2CO

3 + 2H 2SO 4 → Na 2SO 4 + 2H 2O + CO 2 d. 2Na 2SO 4 + 3Bi(NO 3) 3 → Bi 2(SO 4) 3 + 9NaNO 3 e. Sn + 4HNO 3 → SnO 2 + 4NO 2 + 2H 2O
Chemistry
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

The chemical equation that is properly balanced is;

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Explanation:

To solve the question, we note the reactions thus and we look for a reason why the reaction is not balanced as follows.

a. CH₃CHO + 3O₂ → 2CO₂ + 2H₂O

Here we have 7 oxygen atoms in the reactant and 6 in the products

Not balanced

b. NH₄NO₃ → 2H₂O + N₂

Here we have three oxygen in the reactant and four in the products = Not balanced

c. Na₂CO₃ + 2H₂SO₄ → Na₂SO₄ + 2H₂O + CO₂

Here we have 11 oxygen atoms in the reactant and 8 in the products = Not balanced

d. 2Na₂SO₄ + 3Bi(NO₃)₃ → Bi₂(SO 4)₃ + 9NaNO₃

Here  we have 2 Na in the reactants and 9 Na in the products = Not balanced

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Here we have equal number of products and reactants = Balanced chemcal reaction equation.

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Equal masses of water undergo condensation, deposition, evaporation, and sublimation. a) Which process releases the most energy?
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Answer:

A. Condensation

B. Evaporation

Explanation:

Condensation releases energy when water vapor condenses to form water droplets. Evaporation absorbs energy whenever it changes from liquid to gas, the heat from the sun heats the water up and absorbs energy.

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3 years ago
An aqueous solution of a soluble compound (a nonelectrolyte) is prepared by dissolving 33.2 g of the compound in sufficient wate
stiv31 [10]

Answer:

2710.2g/mol

Explanation:

Step 1:

Data obtained from the question. This include the following:

van 't Hoff factor (i) = 1 (since the compound is non-electrolyte)

Mass of compound = 33.2g

Volume = 250mL

Osmotic pressure (Π) = 1.2 atm

Temperature (T) = 25ºC = 25ºC + 273 = 298K

Gas constant (R) = 0.0821 atm.L/Kmol

Molar mass of compound =.?

Step 2:

Determination of the molarity of the compound.

The molarity, M of the compound can be obtained as follow:

Π = iMRT

1.2 = 1 x M x 0.0821 x 298

Divide both side by 0.0821 x 298

M = 1.2 / (0.0821 x 298)

M = 0.049mol/L

Step 3:

Determination of the number of mole of compound in the solution. This can be obtain as follow:

Molarity = 0.049mol/L

Volume = 250mL = 250/1000 = 0.25L

Mole of compound =..?

Molarity = mole /Volume

0.049 = mole / 0.25

Cross multiply

Mole = 0.049 x 0.25

Mole of compound = 0.01225 mole.

Step 4:

Determination of the molar mass of the compound. This is illustrated below:

Mole of the compound = 0.01225 mole.

Mass of the compound = 33.2g

Molar mass of the compound =.?

Mole = Mass /Molar Mass

0.01225 = 33.2/Molar Mass

Cross multiply

0.01225 x molar mass = 33.2

Divide both side by 0.01225

Molar mass = 33.2/0.01225

Molar mass of the compound = 2710.2g/mol

Therefore, the molar mass of the compound is 2710.2g/mol

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25.0 g of barium hydroxide is dissolved in 120.0g of water. What is the morality?
Vinvika [58]
Molarity: M = #moles of solute / liters of solution

# moles = mass / molar mass

Molar mass calculation

Barium hydroxide = Ba (OH)2

Atomic masses
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H=1 g/mol
Molar mass of Ba (OH)2 = 137.4 g/mol + 2*16g/mol + 2*1 g/mol = 171.4 g/mol

# mol = 25.0g/171.4 g/mol = 0.146 mol

For the volume of water use the fact that the density is 1g/ml., so 120 g = 120 ml = 0,120 liters.

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Answer: enzymes.

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