1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ksenya-84 [330]
3 years ago
15

Which one of the following equations is properly balanced? a. CH 3CHO + 3O 2 → 2CO 2 + 2H 2O b. NH 4NO 3 → 2H 2O + N 2 c. Na 2CO

3 + 2H 2SO 4 → Na 2SO 4 + 2H 2O + CO 2 d. 2Na 2SO 4 + 3Bi(NO 3) 3 → Bi 2(SO 4) 3 + 9NaNO 3 e. Sn + 4HNO 3 → SnO 2 + 4NO 2 + 2H 2O
Chemistry
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

The chemical equation that is properly balanced is;

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Explanation:

To solve the question, we note the reactions thus and we look for a reason why the reaction is not balanced as follows.

a. CH₃CHO + 3O₂ → 2CO₂ + 2H₂O

Here we have 7 oxygen atoms in the reactant and 6 in the products

Not balanced

b. NH₄NO₃ → 2H₂O + N₂

Here we have three oxygen in the reactant and four in the products = Not balanced

c. Na₂CO₃ + 2H₂SO₄ → Na₂SO₄ + 2H₂O + CO₂

Here we have 11 oxygen atoms in the reactant and 8 in the products = Not balanced

d. 2Na₂SO₄ + 3Bi(NO₃)₃ → Bi₂(SO 4)₃ + 9NaNO₃

Here  we have 2 Na in the reactants and 9 Na in the products = Not balanced

e. Sn + 4HNO₃ → SnO₂ + 4NO₂ + 2H₂O

Here we have equal number of products and reactants = Balanced chemcal reaction equation.

You might be interested in
a) Calculatethe molality, m, of an aqueous solution of 1.22 M sucrose, C12H22O11. The density of the solution is 1.12 g/mL.b) Wh
Contact [7]

Answer:

a) 1,74 molal

b) 37,2 %

c) 0,03

Explanation:

We are going to define sucrose as solute, water as solvent and the mix of both, the solution.

Let´s start with the data:

Molarity = M = \frac{1,22 mol solute}{lts solution}

We can assume as a calculus base, 1 liter of solution. So, in 1 liter of solution we have 1,22 moles of solute:

1 lts solution * \frac{1,22 moles solute}{lts solution}=1,22 moles solute

Knowing that the molality (m) is defined as mol of solute/kgs solvent, we have to calculate the mass of solvent on the solution. Remember our calculus base (1 lts of solution). In 1 lts of solution we have 1120 grams of solution.

1 lts solution * \frac{1,12 grs solution}{mL solution}*\frac{1000 mL solution}{1 lts solution} = 1120 grs of solution

With the molecular weight of solute (<em>Sum of: for carbon = 12*12=144; for hydrogen = 1*22=22 and for oxygen = 16*11=176. Final result = 342 grs per mol</em>), we can obtain the mass of solute:

1,22 mol solute*\frac{342 grs solute}{1 mol solute} = 417,24 grs solute

Now, the mass of solvent is: mass solvent = mass of solution - mass of solute. So, we have: 1120 - 417,24 = 702,76 grs of solvent = 0,70276 Kgs of solvent

molality = m = \frac{1,22 mol solute}{0,70276 kgs solvent}= 1,74 molal

For b) question we have that the mass percent of solute is hte ratio between the mass of solute and the mass of solution. So,

%(w/w) = \frac{417,24 grs solute}{1120 grs solution} = 37,2%

For c) question we have that the mole fraction of solute is the ratio between moles of solute and moles of solution. Let's calculate the moles of solution as follows: <em>Moles solution = moles solute + moles solvent.</em> First we have that the moles of solvent are (remember that the molecular weight of water for this calculus is 18 grs per mol):

702,76 grs solvent*\frac{1 mol solvent}{18 grs solvent} = 39,04 moles solvent  

So, we have the moles of solution: 1,22 moles of solute + 39,04 moles of solvent = 40,26 moles of solution

Finally, we have:

Mol frac solute = \frac{1,22 mol solute}{40,26 mol solution}= 0,03

6 0
3 years ago
Substance A has the following properties.
givi [52]

A curve of temperature vs. time for the entire heating process.

The sample is heated up to 100.°C, therefore, the heat and time required to heat the sample to its boiling point, the heat and time required to boil the sample, and the heat and time required to heat the sample from its boiling point to 100.°C are needs to be calculated.

i ) Calculating the heat and time required to heat the sample to its boiling point:

Boiling point = 85°C

C(liquid) = 2.5 J/g °C

The heat required up to melting the sample is calculated in the previous parts. Therefore, the heat required to heat the sample from -20°C to 85°C can be calculated as,

Therefore, T f = 85°C  and T i = - 20°C

Plug in the values in the specific heat formula to calculate the heat energy required to heat the sample to its melting point,

q3 = 25 g ×  2.5 J/g °C × [85 - (-20)]°C

     = 25 J/°C ×[85+20]°C

     = 6562.5 J

The total heat energy required for heating the sample from initial temperature to boiling point is:-

q1 + q2 + q3 = 500 J + 4500 J + 6562.5 J

                    = 11562.5 J

The Rate of heating = 450 J/min

450. J = 1 min

   11562.5 J = ? min

11562.5 J × 1min/450 J = 25.69 min

ii) Calculating the heat and time required to boil the sample:

∆H Vap = 500 J/g

The boiling is the phase change from liquid to gas at 85°C, therefore, the heat required to boil the sample can be determined

q4= m × ∆Hvap

    = 25 g × 500 J/g

   = 12500 J

Thus, total heat required to this phase change is q1 + q2 + q3 + q4  = 500 J + 4500 J +6562.5  J + 12500 J = 24062.5 J

The Rate of heating = 450 J / min

450 J = 1 min

24062.5 J = ? min

24062.5J ×  1min / 450 J = 53.47 min

iii) Calculating the heat and time required to heat the sample from its boiling point to 100°C

C gas = 0.5 J / g °C

The heat required to boil the sample is calculated in the previous parts. Therefore, the heat required to heat the sample from 85°C to 100°C can be calculated as,

Therefore, T f = 100.°C  and T i = 85°C

q5 = 25 g ×  0.5 J / g °C × [100 - 85] °C

    = 25 J / °C ×15 °C

    = 187.5  J

The total heat energy required for heating the sample from initial temperature to 100°C is

q1 + q2 + q3 + q4 + q5 = 500 J + 4500 J + 2625J + 12500 J + 187.5 J

                                      =24250 J

The Rate of heating = 450 J / min

  450. J = 1 min

 24250 J=? min

Thus, heating the sample to 100.°C takes a total of 53.89 min.

iv) Draw a curve of temperature vs. time for the entire heating process:-

Temperature °C     Temperature K     Heat energy (J)     Time (min)

 -40 °C                       233                             0                     0

-20 °C                          253                          500                  1.11    

Melting -20 °C             253                        5000                   11.11

85 °C                         358                         11562.5              25.69

Boiling 85 °C             358                           24062.5          53.475              

100  °C                       373                             24250          53.89

Hence, the graph for the result is in the image.

Learn more about temperature here:-brainly.com/question/24746268

#SPJ4

4 0
1 year ago
When you stand on a bathroom scale, what force or forces are acting on you?
Readme [11.4K]

Answer:

B

Explanation:

Lets see here, Gravity is pulling you down but your body is repelling to gravity. Meaning that gravity is pulling down your weight and the scale is reading it.

Hope this helped!

3 0
2 years ago
Read 2 more answers
In the Bohr model, ____ electrons fill the first energy level, ____ electrons fill the second energy level, and ___ electrons fi
Setler [38]
The answer is d Thus, the first energy level holds 2 * 1^2 = 2 electrons, while the second holds 2 * 2^2 = 8 electrons. Each orbital. The third energy level can hold up to 18 electrons, meaning that it is not full when it has only electrons.
8 0
2 years ago
Ammonia and sulfuric acid react to form ammonium sulfate. Determine the starting mass of each reactant if 20.3 g of ammonium sul
strojnjashka [21]
Hope you are able to see

8 0
3 years ago
Other questions:
  • If you combine neon argon and helium what would happen
    15·1 answer
  • What is the chemical equation of photosynthesis
    12·2 answers
  • Air should be classified as:
    15·1 answer
  • Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +
    11·2 answers
  • Think critically explain how biotic change in an ecosystem that has flooded?
    15·1 answer
  • The gas molecules that make up air are in two rooms. The gas molecules in the kitchen are moving faster than the gas molecules i
    15·1 answer
  • 1. When the temperature of a rigid hollow sphere containing 685 L of helium gas is
    6·1 answer
  • Which statement describes the general trends in electronegativity and first ionization energy as the elements in Period 3 are co
    15·2 answers
  • Earthquakes are vibrations of Earth's crust. Which of the following is used to
    15·1 answer
  • How many moles of water are produced when 2 moles of NaHCO3 react with 2 moles of HCI?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!