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2 years ago

Which substance is liquid at 0°C? 1. alcohol 2. aluminum 3. ammonia 4. copper

Chemistry

1 answer:

Tanya [424]2 years ago

5 0

Alcohol, alcohol is the only liquid since copper and aluminum are a solid ammonia is a bacteria

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PLEASE HELP MY TEACHER IS GOING TO SEE ME AFTER CLASS

Crazy boy [7]

Answer:

The Nucelous helps prevent bad cells in

Explanation:

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2 years ago

Atomic numbers of atoms of elements _____ as you read _____ along each row of the periodic table of the elements.

serious [3.7K]

The periodic table increases as you read left to right so it is A.

8 0

3 years ago

Read 2 more answers

Rewrite the equation below using the correct conventions for stoichiometric coefficients. 2 BaCl2 + 2 H2SO4 → 2 BaSO4 + 4 HCl

vichka [17]

Answer:

$BaCl2+H2SO4 \rightarrow BaSO4+2HCl$

Explanation:

The given equation is:

$2 BaCl2+2H2SO4 \rightarrow2BaSO4+4HCl$

Based on the reaction stoichiometry:

2 moles of barium chloride (BaCl2) reacts with 2 moles of sulfuric acid (H2SO4) to form 2 moles of barium sulfate (BaSO4) and 4 moles of HCl

Although the reaction is balanced, the correct convention is to depict reactions in terms of the lowest molar ratio. Therefore the coefficients (2,2,4 and 4) can be divided by 2 to give:

$BaCl2+H2SO4 \rightarrow BaSO4+2HCl$

6 0

2 years ago

A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil

Flura [38]

Answer: Molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.049g}{95g/mol}=5.2\times 10^{-4}moles$

$V_s$ = volume of solution in ml = 100 ml

Now put all the given values in the formula of molarity, we get

$Molarity=\frac{5.2\times 10^{-4}moles\times 1000}{100ml}=5.2\times 10^{-3}mole/L$

Therefore, the molarity of solution will be $5.2\times 10^{-3}mole/L$

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

As 1 mole of $MgCl_2$ gives 2 moles of $Cl^-$

Thus $5.2\times 10^{-3}$ moles of $MgCl_2$ gives = $\frac{2}{1}\times 5.2\times 10^{-3}=0.0104$

Thus the molarity of $Cl^-$ anions in the chemist's solution is 0.0104 M

6 0

2 years ago

In hydrate ratio does the mass of salt come first or does the mass of water

frutty [35]

CuSO4 *5H20
In the formula of the hydrate, on the first place is the salt and on the second of water. so in ration on the first place should be salt also.

6 0

2 years ago