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stepan [7]
3 years ago
12

What is the volume of a 4.0 M solution of KCl that contains 8.0 moles of solute?

Chemistry
1 answer:
kenny6666 [7]3 years ago
6 0
Molarity is defined as the number of moles dissolved in 1 L of solution.
The molarity of KCl has been given as 4.0 M
This means that in 1 L of KCl solution, there are 4 moles dissolved.
We have been asked to find the volume of the solution if there are 8.0 moles of solute.
If 4 moles are in - 1 L of solution
Then 8 moles of solute are in - 1/4 x 8 = 2 L solution
Volume of KCl solution is 2 L.
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On the basis of the Ksp values below, what is the order of the solubility from least soluble to most soluble for these compounds
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The order of solubility is AgBr <   Ag₂CO₃ < AgCl

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Comparing AgBr: Ksp = 5.4 x 10⁻¹³ with AgCl: Ksp = 1.8 x 10⁻¹⁰, AgCl will be more soluble.

Comparing Ag2CO3: Ksp = 8.0 x 10⁻¹²  with AgCl Ksp = AgCl: Ksp = 1.8 x 10⁻¹⁰ we have the complication of  the ratio of ions 2:1 in Ag2CO3,  so the answer is not obvious. But since we know that

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Ksp = s² = 1.8 x 10⁻¹⁰  ∴ s = √ 1.8 x 10⁻¹⁰   = 1.3 x 10⁻⁵

Therefore, AgCl is more soluble than Ag₂CO₃

The order of solubility is AgBr <   Ag₂CO₃ < AgCl

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