The presence of H3O+ is the hydronium ion, and one definition of an acid is something that donates a proton (H+). HCl in this case does just that. Basic solution forming with NaOH and water: ... NaOH + H2O ==>Na+ + OH- so it donates or produces OH- ions, thus making a basic solution
Answer:
atomic number
Explanation:
mass is determined by the protons and neutrons
The concentration (in M) of hydroxide ions in a solution at 25°C with a pOH of 3.58 is 2.6 × 10⁻⁴ M.
pOH is the measure of basic nature of a solution by evaluating the [OH⁻] concentration.
It is the negative logarithm of the hydroxide ion concentration.
Given,
pOH = 3.58
Temperature = 25°C = 298K
At 25°C, the relation of pOH and [OH⁻] concentration is as follows:
∴ pOH = -log [OH⁻]
⇒ 3.58 = -log [OH⁻]
⇒log [OH⁻] = -3.58
⇒ [OH⁻] = antilog (-3.58)
⇒[OH⁻] = 2.6 × 10⁻⁴ M
The concentration (in m) of hydroxide ions in a solution at 25.0 °C with a pOH of 3. 58 is 2.6 × 10⁻⁴ M.
Learn more about pOH here, brainly.com/question/17144456
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Answer:
The answer to your question is below
Explanation:
Trial 1 Trial 2
mass of Mg 0.255 g 0.353 g
mass of MgO 0.418 g 0.576 g
Chemical reaction
2Mg(s) + O₂(g) ⇒ 2MgO(s)
Question 1.
Atomic mass of Mg = 24.31 x 2 = 48.62 g
Molecular mass of MgO = 2(24.31 + 16) = 80.62 g
Trial 1
48.62 g of Mg ----------------- 80.62 g of MgO
0.255 g ---------------- x
x = (0.255 x 80.62)/48.62
x = 0.422 g of MgO
Trial 2 48.62 g of Mg ----------------- 80.62 g of MgO
0.353 g ---------------- x
x = (0.353 x 80.62)/48.62
x = 0.585 g of MgO
Question 2
Trial 1
Percent yield = 0.418/0.422 x 100 = 99%
Trial 2
Percent yield = 0.576/0.585 x 100 = 98.5%
Question 3
Average = (99 + 98.5)/2
= 98.75%
