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ziro4ka [17]
4 years ago
13

A water sample contains the pollutant chlorobenzene with a concentration of 15 ppb. What is the molarity of this solution? Assum

e the density of the solution is 1.00 g/mL. The molar mass of chlorobenzene is 112.6 g/mol.
Chemistry
1 answer:
solniwko [45]4 years ago
7 0

Answer:

The molarity is 1.33×10^-7M

Explanation:

15ppb = 15g of chlorobenzene/10^9g of solution × 1 mole of chlorobenzene/112.6g × 1g of solution/mL = 1.33×10^-10mol/mL × 1000mL/1L = 1.33×10^-7mol/L

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Attached is the balanced chemical equation xx

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Which is the smallest?<br> A) 1.3 x 1020<br> B) 2.9 x 1021<br> C) 9.5 x 1032<br> d) 8.4 x 1019
alexgriva [62]
Answer: A, 1.3*1020, 1326

A. 1326

B. 2960.9

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7 0
3 years ago
Read 2 more answers
Consider these generic half-reactions. Half-reaction E° (V) X+(aq)+e−⟶X(s) 1.52 Y2+(aq)+2e−⟶Y(s) −1.17 Z3+(aq)+3e−⟶Z(s) 0.84 Ide
olya-2409 [2.1K]

Answer:

     strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

     X^{+} will oxidize Z

Explanation:

The higher the reduction potential of a species, higher will be the tendency to consume electrons from another species. Hence higher will be the oxidizing power of it's oxidized form and lower will be the reducing power of it's reduced form.

Alternatively, higher reduction potential value suggests that the oxidized form of the species acts as a stronger oxidizing agent and the reduced form of the species acts as a weaker reducing agent.

Order of reduction potential:

                       E_{X^{+}\mid X}^{0}(1.52V)> E_{Z^{3+}\mid Z}^{0}(0.84V)> E_{Y^{2+}\mid Y}^{0}(-1.17V)

So, strongest oxidizing agent: X^{+}

     weakest oxidizing agent: Y^{2+}

     strongest reducing agent: Y

     weakest reducing agent: X

As reduction potential of the half cell X^{+}\mid X is higher than the reduction potential of the half cell Z^{3+}\mid Z therefore X^{+} will oxidize Z into Z^{3+} and itself gets converted into X.

     

5 0
3 years ago
Please answer for me.
jeka94

Answer:

54.5%

Explanation:

The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:

Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)

= 72 + 8 + 96

= 176 g/mol

Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:

Mass of Oxygen = 16 × 6 = 96 g

Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:

Percentage of oxygen =

Mass of Oxygen/mass of C₆H₈O₆ × 100

Percentage of oxygen = 96 / 176 × 100

Percentage of oxygen = 54.5%

Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.

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3 years ago
Increasing the temperature of a swimming pool causes the water molecules to
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I cause the water to het up, when it do it become a gas.
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