Answer : Option B) 360 g/mol
Explanation : The antibacterial agent Penicillin N contains 8.92% of sulfur by mass. So we have to calculate the molar mass of penicillin N will be as
i) 256 X 0.0892 = 22.83 g/mol this cannot be the answer as it doesn't shows any sign of sulfur being present even in 1 mole.
ii) 360 X 0.0892 = 32.112 g/mol This is the closest to the molar mass of sulfur which is 32.06 g/mol; this means it contains 1 mole of sulfur.
iii) 390 X 0.0892 = 34.78 g/mol this also fails to prove the answer as correct.
iv) 743 X 0.0892 = 66.27 g/mol This is not even falling in the range of sulfur mole.
Hence we can confirm that the answer is Option B
Answer:
C₆H₁₂O₆ (glucose)
A molecular substance.
Explanation:
C₆H₁₂O₆ does not dissociate. It is not a ionic type.
There is no metal in the compound, it is not a metallic type.
Glucose is an organic molecule, a type of carbohidrate, the most common from the monosaccharides type.
Answer:
Exercise 1
a) 140 m
b) 100 m
c) 180 m
d) 140 m
Exercise 2
a) 20 yards
b) 30 yards
c) 20 yards
d) 55 yards
Exercise 3
a) 11 Kilometers
b) 7 Kilometers
Explanation:
Exercise 1
Distance from B to C = 140 m
Distance from to D = 100 m
Total distance = 100+40+40 = 180 m
Total displacement i.e. distance between A and D is 140 m
Exercise 2
a) Distance from B to C = 35 -15 = 20 yards
b) Distance from C to D = 5 + 35 = 30 yards
c) Distance from B to D = 5 + 15 = 20 yards
d) Displacement = 5 + 50 = 55 yards
Exercise 3
a) The total distance travelled = 5 + 2 + 4 = 11 Kilometers
b) Displacement = 5-2 + 4 = 7 Kilometers
Answer:
1019.27 g.
Explanation:
- For the balanced reaction:
<em>2Na + Cl₂ → 2NaCl,</em>
It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.
- Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:
2 moles of Na need → 1 mol of Cl₂, from the stichiometry.
57.5 moles of Na need → ??? mol of Cl₂.
<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>
<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>
