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suter [353]
3 years ago
14

Which change favors the products in this reversible reaction n2o4(g)+58 kj 2no2 (g)?

Chemistry
2 answers:
Fiesta28 [93]3 years ago
8 0

Answer:

increase in pressure

Explanation:

Ksenya-84 [330]3 years ago
7 0

<span>According to Le Chatelier's Principle, the position of equilibrium moves to counteract the change, the position of equilibrium will move so that the concentration of products of chemical reaction increase, if:</span>

<span>1) increase temperature, because this endothermic reaction.</span>

<span>2) increase concentration of reactant.</span>

<span>3) decrease pressure of the system, so reaction moves to direction where is more molecules.</span>

<span>
</span>

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PLEASE HELP WILL GIVE BRAINLIEST
bija089 [108]

Answer:

sorry i'm not a scientist but i think it's C

Explanation:

sorry again if i get it wrong for u :(

3 0
2 years ago
Calculate the value of the equilibrium constant, Kc, for the reaction below, if 0.208 moles of sulfur dioxide gas, 0.208 moles o
Harman [31]
First, we convert the moles of each substance into the concentration using the volume of the reactor.
[SO₃] = 0.425/1.5 = 0.283 M
[SO₂] = 0.208 / 1.5 = 0.139 M
[O₂] = 0.208/1.5 = 0.139 M
The equilibrium constant is calculated by:
Kc = [SO₃]² / [O₂][SO₂]²
Kc = (0.283)²/(0.139)(0.139)²
Kc = 29.8 = 2.98 x 10¹

The answer is C
8 0
3 years ago
The weather report says that if the temperature drops 10°, it will reach 25° below zero. The current temperature T can be found
Neporo4naja [7]

Answer:

The current temperature is -15° (15° below zero)

Explanation:

The temperature drops 10°:

T-10°

It will reach 25° below zero:

T - 10° = -25°

We add 10° in both members of the equation:

T - 10° +10° = -25° +10°

The equation is simplified as follows:

T = -25° +10°

T = -15°

The integer -15° can be expressed as 15° below zero.

8 0
2 years ago
What is the molality of a solution made by dissolving 15.20 g of i2 in 1.33 mol of diethyl ether, (ch3ch2)2o?
Paraphin [41]
The  molarity   of solution  made  by  dissolving  15.20g  of i2  in 1.33 mol  of diethyl ether (CH3CH2)2O  is    =0.6M

   calculation

molarity  =moles of solute/  Kg of the  solvent

mole  of the solute  (i2)  =  mass /molar mass
the molar mass of i2 = 126.9 x2 = 253.8 g/mol

moles is therefore=  15.2 g/253.8 g/mol  =  0.06  moles


calculate the Kg of solvent  (CH3CH2)2O
mass =  moles  x  molar mass
molar mass  of  (CH3CH2)2O= 74 g/mol

mass  is therefore = 1.33 moles  x  74 g/mol =  98.42 grams
in Kg = 98.42 /1000 =0.09842  Kg

molarity  is therefore = 0.06/0.09842 = 0.6 M

3 0
3 years ago
How many atoms are in 4.93 moles hcl?
trasher [3.6K]
1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??

4.93 x ( 6.02x10²³) / 1 = 

=> 2.96x10²⁴ atoms
4 0
3 years ago
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