Answer:
option C. it contain 6 neutrons.
Explanation:
Answer:
Answer D => E°(Mg°/Cu⁺²) = 0.34 + 2.37 = 2.71v
Explanation:
(Oxidation) => Mg°(s) => Mg⁺²(aq) + 2e⁻ E°(Mg°/Mg⁺²) = -2.37 v
(Reduction) => Cu⁺²(aq) + 2e⁻ => Cu°(s) E°(Cu⁺²/Cu°) = +0.34 v
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Net Rxn => Mg°(s) + Cu⁺²(aq) => Mg⁺²(aq) + Cu°(s)
Std Cell Potential (25°C/1Atm) = E°(Redn) = E°(Oxidn) = +0.34v - (-2.37v)
= 0.34v + 2.37v = 2.72v
Main sequence stars with low temperatures tend to have low luminosity is based on Hertzprung-Russell diagram
<h3>What is the Hertzsprung-Russell diagram's main sequence?</h3>
The bright, hot stars in the image's upper left are the main sequence group, which stretches roughly diagonally to the lower right (dim and cool). In the bottom left are white dwarfs, which are small, faint, and hot. In the top right are giant and supergiant stars, which are big, bright, and cool.
<h3>What is the main sequence star H-R diagram trend?</h3>
Main sequence stars have a wide range of effective temperatures, but because they are brighter at higher temperatures, they normally follow a band from the bottom right to the top left of the diagram. Inside the cores, hydrogen and helium are fusing together.
To know more about H-R diagram visit:
brainly.com/question/13635125
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