Answer:
Explanation:
Mechanical energy = Gravitational potential energy + kinetic energy
Time Gravitational potential energy kinetic energy Total ME
0 4 0 4
2 2 2 4
4 0 4 4
6 2 2 4
8 4 0 4
and so on .....
We see that total mechanical energy is always 4 which is constant .
So gravitational and kinetic energy changes cyclically but total mechanical energy is constant .
Answer:
Molar mass of the gas = 15.15 g/mol
Explanation:
PV = nRT
Where,
P = pressure
n = No. of moles
R = Gas constant
T = Temperature
P = 698 torr, 1 torr = 0.00131579 atm

Temperature = 111 °C = 100 + 273.15 = 384.15 K
V = 48.7 L
R = 0.082057 L atm/mol K
Now, PV = nRT


=1.4189 mol
Molar mass = Mass/ No. of moles
= 21.5/1.4189
=15.15 g/mol
Answer: Red blood cells
Explanation:
oxygen moves thru hemoglobin
Answer:
Second order
Explanation:
Given that:
When the reaction A → B + C is studied, a plot 1/[A]t vs. time gives a straight line with a positive slope.
From the integration method for the second order of reaction.
Suppose that:
rate = k₂[A]²
∴

Therefore, a plot of the linear function
versus t will be linear with a positive slope k₂ and the intercept on the concentration axis will be 
The linear plot for a second order reaction can be seen in theimage attached below.
The reaction between the reactants would be:
CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻
Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.
CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I 0.11 0 0
C -x +x +x
E 0.11 - x x x
Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
Since the given information is Kb, let's find Ka in terms of Kb.
Ka = Kw/Kb, where Kw = 10⁻¹⁴
So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]
Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>