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miv72 [106K]
3 years ago
10

What is the net force of a 25 g object with an acceleration of 3 m/s^2? 100PTS

Physics
2 answers:
gayaneshka [121]3 years ago
5 0

Explanation:

Force=Mass×acceleration

force=25×3

force=75N

sertanlavr [38]3 years ago
5 0

Answer:

0.75 N

Explanation:

F=ma

mass change to kg -> 25 g to 0.25 Kg

0.25x3 =0.75 N

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A wave on a string has a wavelength of 0.90 m at a frequency of 600 Hz. If a new wave at a frequency of 300 Hz is established in
kobusy [5.1K]

Answer:

 λ₂ = 1.8 m

Explanation:

given,

wavelength of the string 1 = 0.90 m

frequency of the string 1 = 600 Hz

wavelength of string 2 = ?

frequency of the string 2 = 300 Hz

we now,

f\ \alpha\ \dfrac{1}{\lambda}

now,

\dfrac{f_1}{f_2}=\dfrac{\lambda_2}{\lambda_1}

\dfrac{600}{300}=\dfrac{\lambda_2}{0.9}

λ₂ = 2 x 0.9

 λ₂ = 1.8 m

Hence, the wavelength of the second string is equal to  λ₂ = 1.8 m

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3 years ago
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evablogger [386]

Answer:

The answer is left

Explanation:

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3 years ago
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A 210 Ohm resistor uses 9.28 W of
IgorLugansk [536]
  • Resistance=R=210Ohm
  • Power=9.28W=P

Current=I

\boxed{\sf P=I^2R}

\\ \sf\longmapsto I^2=\dfrac{P}{R}

\\ \sf\longmapsto I^2=\dfrac{9.28}{210}

\\ \sf\longmapsto I^2\approx0.04

\\ \sf\longmapsto I\approx\sqrt{0.04}

\\ \sf\longmapsto I\approx\sqrt{\dfrac{4}{100}}

\\ \sf\longmapsto I\approx\dfrac{\sqrt{4}}{\sqrt{100}}

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4 0
3 years ago
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8 0
3 years ago
A mountain-climber friend with a mass of 74 kg ponders the idea of attaching a helium-filled balloon to himself to effectively r
bazaltina [42]

Answer:

V=16.65 m^3

Explanation:

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reduce 25% from 74kg

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18.5kg*g=(1.29kg/m^3-0.179kg/m^3*)V*g

V=\frac{18.5kg}{(1.29-0.179)kg/m^3}

V=16.65 m^3

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3 years ago
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