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Brums [2.3K]
3 years ago
7

How high has a 45 g golf ball been driven if it has a potential energy of 2.06 J?

Physics
2 answers:
Mice21 [21]3 years ago
7 0
PE=mgh
2.06 J = 2.06 kg·m²/s² = (0.045 kg)·(9.8 m/s²)·h
where h is the height the ball has reached
Solve for h:
h = 2.06/(0.045·9.8) = 4.67 to the nearest hundredth
h = 4.67 m

nydimaria [60]3 years ago
4 0
Here, U = mgh

We have: m = 45 g = 0.045 Kg
U = 2.06 J, g = 9.8 m/s², h = ?

Substitute the values in the formula:
2.06 = 0.045 × 9.8 × h
2.06 = 0.441 × h
h = 2.06 / 0.441
h = 4.67 m

In short, your final answer would be 4.67 meters

Hope this helps!

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Explanation:

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Describe a sea-level transgression
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Answer:

correct option is a. True

Explanation:

solution

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4 0
3 years ago
Which data set has the largest range?
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Answer:

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3 0
3 years ago
Just this last one!!
Pepsi [2]

Answer:

47 \ \frac{m}{s}

Explanation:

s = displacement (m)

u = initial velocity (\frac{m}{s})

v = final velocity (\frac{m}{s})

a = acceleration (\frac{m}{s^{2} })

t = time (s)

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4 0
2 years ago
Read 2 more answers
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