Answer:8.28 km
Explanation:
Given
First it drifts
2.5 km

Secondly it drifts
4.70 km

After that it drifted along east direction 5.1 km

After that it drifts
7.2 km

After that it drifts
2.8 km

=
+![\left [ 2.5sin45-4.7sin60-7.2sin55+2.8sin5\right ]\hat{j}](https://tex.z-dn.net/?f=%5Cleft%20%5B%202.5sin45-4.7sin60-7.2sin55%2B2.8sin5%5Cright%20%5D%5Chat%7Bj%7D)


for direction

south of east
Answer: <u>D. An AC circuit</u>
Explanation:
I took it on a test and it was correct ; )
Answer:
connect two 9 ohms resistance in series now it becomes 18 ohm
Answer:
Vd = 1.597 ×10⁻⁴ m/s
Explanation:
Given: A = 3.90×10⁻⁶ m², I = 6.00 A, ρ = 2.70 g/cm³
To find:
Drift Velocity Vd=?
Solution:
the formula is Vd = I/nqA (n is the number of charge per unit volume)
n = No. of electron in a mole ( Avogadro's No.) / Volume
Volume = Molar mass / density ( molar mass of Al =27 g)
V = 27 g / 2.70 g/cm³ = 10 cm³ = 1 × 10 ⁻⁵ m³
n= (6.02 × 10 ²³) / (1 × 10 ⁻⁵ m³)
n= 6.02 × 10 ²⁸
Now
Vd = (6A) / ( 6.02 × 10 ²⁸ × 1.6 × 10⁻¹⁹ C × 3.9×10⁻⁶ m²)
Vd = 1.597 ×10⁻⁴ m/s
The kinetic energy of the child at the bottom of the incline is 106.62 J.
The given parameters:
- <em>Mass of the child, m = 16 kg</em>
- <em>Length of the incline, L = 2 m</em>
- <em>Angle of inclination, θ = 20⁰</em>
The vertical height of fall of the child from the top of the incline is calculated as;

The gravitational potential energy of the child at the top of the incline is calculated as;

Thus, based on the principle of conservation of mechanical energy, the kinetic energy of the child at the bottom of the incline is 106.62 J since no energy is lost to friction.
Learn more about conservation of mechanical energy here: brainly.com/question/332163