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sineoko [7]
3 years ago
14

In a hotel, Elevator 1 stops at the third floor at an elevation of 40ft. Elevator 2 stops at the parking level at an elevation o

f -25ft.
How far apart, in feet, are the two elevators? Show or explain your work.

PLEASEEE ANSWER!!!
Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

65 ft

Step-by-step explanation:

Negative and positive numbers can be expressed as how far away they are from zero.

40 is 40 units away from zero. Elevator 1 is 40 units from 0.

-25 is 25 units away from zero. Elevator 2 is 25 units from 0.

To find the distance, we'll add their distances from 0.

40 + 25 = 65

They are 65 units apart. In your problem you specify feet, so they are 50 ft apart.

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Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
frez [133]

Answer:

1) H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

2) The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married                     21                              37                            58                116

Not Married              59                             63                            42                164

Total                          80                             100                          100              280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is independence between the marital status and the diagnostic of alcoholic

H1: There is association between the marital status and the diagnostic of alcoholic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

Part 3

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Diag. Alcoholic   Undiagnosed Alcoholic    Not alcoholic    Total

Married             33.143                       41.429                        41.429                116

Not Married     46.857                      58.571                        58.571                164

Total                   80                              100                             100                 280

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{33.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=5.22x10^{-5}

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p value is lower than the significance level so then we can reject the null hypothesis at 5% of significance, and we can conclude that we have association between the two variables analyzed.

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Answer:

Step-by-step explanation:

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If you are given the length of a hypotenuse and the length of an adjacent side, what
Evgen [1.6K]

Answer:

cosine

Step-by-step explanation:

6 0
2 years ago
At a mortgage company, 60% of calls are answered by an attendant. The remaining 40% of callers leave their phone numbers. Of the
ludmilkaskok [199]

Answer:

  24/35, about 69%

Step-by-step explanation:

The data given can be put into a 2-way table (attached). It shows that 0.48 of all calls were answered and resulted in a mortgage application. Altogether, 0.70 of all calls resulted in a mortgage application. Thus the conditional probability of interest is ...

  p(spoke to attendant | applied for a mortgage) = p(spoke & applied)/p(applied)

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3 years ago
F(x) = -x + 5, what is the value of f(-4)?<br> I
liberstina [14]

Answer:

Step-by-step explanation:

F(x)=-x+5

So

f(-4)= -(-4)+5

f(-4)= 4+5

f(-4)= 8

Only we have to substitute value of x then after simplification we will get answer..Hope this will help

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3 years ago
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