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Fiesta28 [93]
3 years ago
5

The heat of fusion of water is 80 cal/ g. How much energy is needed to melt 0.05 kg of ice?

Chemistry
1 answer:
Alex Ar [27]3 years ago
7 0
80 cal/ g is same as 80 calories in each 1 gram. so,

80 cal= 1 gram

first, we need to convert the kg into grams. all you have to do is multiply by 1000 or move the decimal three times to the right. 

0.05 kg= 50.0 grams

50.0 g (80 cal/ 1 gram)= 4000 calories

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What is the wavelength of a 2500 kg truck traveling at a rate of 75km/h?
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m = mass of the truck traveling = 2500 kg

v = speed of the truck traveling = 75 km/h = 75 (km/h) (1000 m/ 1 km) (1 h /3600 sec) = 20.83 m/s

h = plank's constant = 6.63 x 10⁻³⁴

λ = wavelength of truck = ?

according to de broglie's principle, wavelength of truck is given as

λ = h/(mv)

inserting the values in the above equation

λ = (6.63 x 10⁻³⁴)/((2500) (20.83))

λ = 1.3 x 10⁻³⁸ m

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3 years ago
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What is TRUE of a mixture?
jolli1 [7]

Answer:

It retains the properties of the substances that make it up

Explanation:

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3 years ago
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A sample of Xe gas is observed to effuse through a pourous barrier in 4.83 minutes. Under the same conditions, the same number o
Solnce55 [7]

Answer:

28.93 g/mol

Explanation:

This is an extension of Graham's Law of Effusion where \frac{R1}{R2} = \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}

We're only talking about molar mass and time (t) here so we'll just concentrate on \sqrt{\frac{M2}{M1} } = \frac{t2}{t1}. Notice how the molar mass and time are on the same position, recall effusion is when gas escapes from a container through a small hole. The time it takes it to leave depends on the molar mass. If the gas is heavy, like Xe, it would take a longer time (4.83 minutes). If it was light it would leave in less time, that gives us somewhat an idea what our element could be, we know that it's atleast an element before Xenon.

Let's plug everything in and solve for M2. I chose M2 to be the unknown here because it's easier to have it basically as a whole number already.

\sqrt{\frac{M2}{131} } = \frac{2.29}{4.83}

The square root is easier to deal with if you take it out in the first step, so let's remove it by squaring each side by 2, the opposite of square root essentially.

(\sqrt{\frac{M2}{131} } )^2= (\frac{2.29}{4.83})^2

{\frac{M2}{131} } = (0.47)^2

{\frac{M2}{131} } = 0.22

M2= 0.22 x 131

M2= 28.93 g/mol

8 0
3 years ago
William adds two values , following the rules for using significant figures in computations. He should write the sum of these tw
yuradex [85]

Answer:

when it comes to adding or subtracting numbers, his final answer should have the same number of decimal places as the least precise value.

For example if you add 2 numbers; 10.443 + 3.5 , 10.443 has 3 decimal places and 3.5 has only one decimal place.

Therefore 3.5 is the less precise value.

So when adding these 2 values the final answer should have only one decimal place.

after adding we get 13.943 but it can have upto one decimal place. then the second decimal place is less than 5 so the answer should be rounded off to 13.9.

the answer is the same number of decimal places as the least precise value

Explanation:

I think this is the answer I'm not sure

7 0
3 years ago
If the volame ofa gas coetainer at 32°C changes froem 1.55 L to 753 ml, what will the final temperature be? Assume the pressure
motikmotik

Answer : The final temperature of gas will be, 149 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{V_2}=\frac{T_1}{T_2}

where,

V_1 = initial volume of gas = 1.55 L

V_2 = final volume of gas = 753 ml  = 0.753 L

T_1 = initial temperature of gas = 32^oC=273+32=305K

T_2 = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

\frac{1.55L}{0.753L}=\frac{305K}{T_2}

T_2=149K

Therefore, the final temperature of gas will be, 149 K

7 0
3 years ago
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