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Rank the following in terms of decreasing miscibility in C₈H₁₈ (octane), a major component of gasoline:

Answer:

In order of decreasing miscibility

C₉H₂₀ (nonane)→C₂H₅F (fluoroethane)→C₂H₅Cl (chloroethane)→H₂O (water)

Explanation:

The solubility of a solid is a measure of its ability to dissolve in a liquid while for liquids, the miscibility is a measure of thhe liquid to mix with anoyjer liquid resulting in a soltion which can hold any amount of either liquids. Immiscible liquids are those that are not soluble or have very limited solibility with each other.

C₉H₂₀ (nonane)→C₂H₅F (fluoroethane)→C₂H₅Cl (chloroethane)→H₂O (water)

In the order of decreasing miscibility as like dissolve like, ability to dissociate and polar and organic characteristics are considered

6 0

4 years ago

In a chemical change molecules DO NOT create or break chemical bonds to form a new substance you might be able to observe a chem

vesna_86 [32]

Answer:

false

Explanation:

3 0

3 years ago

An iron nail rusts when exposed to oxygen. According to the following reaction, how many grams of iron(III) oxide will be formed

natka813 [3]

Answer: 103.8 g of $Fe_2O_3$ , 0.65 moles of

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{31.1}{32}=0.975moles$

Thus $O_2$ is the limiting reagent as it limits the formation of product and $Fe$ is the excess reagent.

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3$

According to stoichiometry :

3 moles of $O_2$ produce = 2 moles of $Fe_2O_3$

Thus 0.975 moles of $O_2$ will produce= $\frac{2}{3}\times 0.975=0.65moles$ of $Fe_2O_3$

Mass of $Fe_2O_3=moles\times {\text {Molar mass}}=0.65moles\times 159.69g/mol=103.8g$

Thus 103.8 g of $Fe_2O_3$ will be produced.

7 0

3 years ago

In a first–order reaction (A → B and rate = k [A]), tripling the concentration of A will have what effect on the reaction rate?

drek231 [11]

Your answer is b just got done doing mine .

3 0

3 years ago

Read 2 more answers

Ferrophosphorus (Fe2P) reacts with pyrite (FeS2) producing iron(II) sulfide and a compound that is 27.87% P and 72.13% S by mass

k0ka [10]

Answer:

The molecular formula of the compound = $P_4S_{10}$

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

Explanation:

Compound that is 27.87% P and 72.13% S by mass and has a molar mass of 444.56 g/mol.

Molar mass of compound = 444.56 g/mol

Number of phosphorus atom = x

Number of sulfur atom = y

Atomic mass of phosphorus 31 g/mol

Atomic mass of sulfur = 32 g/mol

Percentage of element in compound :

$=\frac{\text{number of atoms}\times text{Atomic mass}}{\text{molar mas of compound}}\times 100$

Phosphorus :

$27.87\%=\frac{x\times 31 g/mol}{444.56 g/mol}\times 100$

x = 4

Sulfur :

$72.13\%=\frac{y\times 32 g/mol}{444.56 g/mol}\times 100$

y = 10

The molecular formula of the compound = $P_4S_{10}$

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

The empirical formula of the compound = $P_2S_{5}$

The balanced chemical equation for this reaction:

$4Fe_2P+18FeS_2\rightarrow 26FeS+P_4S_{10}$

8 0

4 years ago