Answer:
it is simple true and thanks for point
Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be
and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =
2. percentage of s character in
hybrid orbital =
3. percentage of s character in
hybrid orbital =
Thus percentage of s-character in an sp hybrid is 50%.
Cu =63.5
2 times N =28.02
6 times O =96
96=63.5=28.02=127.07
122/127.07=.96 molecules