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2 years ago

using your age to the nearest whole number and ignoring leap years how many seconds have you been alive

Mathematics

1 answer:

vfiekz [6]2 years ago

6 0

Answer:

409968000

Step-by-step explanation:

13 rounded years is equal to 409968000 seconds

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In a recent year, an author wrote 171 checks. Use the Poisson distribution to find the probability that, on a randomly selecte

sveticcg [70]

Answer: 0.3741

Step-by-step explanation:

Poison probability ;

P(x) = [U(^x) e(^-U)] ÷ x!

Where U = mean

Note: e = exponential symbol

Number of checks that year = 171

Number of days in a year = 365

U = 171/365 = 0.468

Average checks per day = 0.4685

Probability that at least one check was written per day is can be calculated by;

P(not 0) = 1 - P(0)

Therefore,

P(x) = [U(^x) e(^-U)] ÷ x!

P(0) = [ 0.4685^0 * e^-0.4685] ÷ 0!

P(0) = [ 1 * 0.6259] ÷ 1

P(0) = 0.6259

Therefore,

P(not 0) = 1 - 0.6259 = 0.3741

4 0

2 years ago

The table below shows some inputs and outputs of the invertible function f with domain all real numbers.

Neko [114]

The value of f⁻¹(f(58)) is 58 and the value of the function f(f(5)) is 11

<h3>How to solve the function values?</h3>

As a general rule, we have:

f⁻¹(f(x)) = x

Substitute 58 for x

So, we have:

f⁻¹(f(58)) = 58

Hence, the value of f⁻¹(f(58)) is 58

Also, we have:

f(f(5))

From the table, we have:

f(5) = 9

So, we have:

f(f(5)) = f(9)

From the table, we have:

f(9) = 11

So, we have:

f(f(5)) = 11

Hence, the value of the function f(f(5)) is 11

Read more about invertible function at:

brainly.com/question/14391067

#SPJ1

7 0

1 year ago

Who is good at basic math?

quester [9]

Just divide the numbers in their decimal for like 12 would be .12

8 0

3 years ago

Read 2 more answers

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

6 0

2 years ago

BRAINLIEST ANSER!!! HELP ME ASAP!!! PLEASSEEE! determine the volume of a cylindrical bucket if the diameter is 8.5 inches and th

yarga [219]

The answer should be 652.2

8 0

3 years ago