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Ostrovityanka [42]
3 years ago
14

Why couldn't you substitute 3m H2SO4 for concentrated HNO3 when oxidizing copper?

Chemistry
2 answers:
schepotkina [342]3 years ago
5 0

This question seems to be an essay question from experiment. Different solution of oxidizing agent will have different strength.  Sulfuric acid or H2SO4 is weaker oxidizing agent when compared to nitric acid (HNO3). In this case, if you subtitute the H2SO4 you wouldn't be able to get the same result for the experiment.



V125BC [204]3 years ago
5 0
<h2>Answer:</h2>

Every oxidizing agent has different properties and they are specific for different reagents. Different solution of oxidizing agent will have different strength.

Sulfuric acid or H2SO4 is weaker oxidizing agent when compared to nitric acid (HNO3). so when you use H2SO4 for the oxidizing copper it would not work because copper need strong oxidizing agent.


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Phosphorous trichloride (PCl3) is produced
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The percentage yield obtained from the given reaction above is 74.8%

<h3>Balanced equation </h3>

P₄ + 6Cl₂ → 4PCl₃

Molar mass of P₄ = 31 × 4 = 124 g/mol

Mass of P₄ from the balanced equation = 1 × 124 = 124 g

Molar mass of PCl₃ = 31 + (35.5×3) = 137.5 g/mol

Mass of PCl₃ from the balanced equation = 4 × 137.5 = 550 g

<h3>SUMMARY</h3>

From the balanced equation above,

124 g of P₄ reacted to produce 550 g of PCl₃

<h3>How to determine the theoretical yield </h3>

From the balanced equation above,

124 g of P₄ reacted to produce 550 g of PCl₃

Therefore,

79.12 g of P₄ will react to produce = (79.12  × 550) / 124 = 350.9 g of PCl₃

<h3>How to determine the percentage yield </h3>
  • Actual yield of PCl₃ = 262.6 g
  • Theoretical yield of PCl₃ = 350.9 g
  • Percentage yield =?

Percentage yield = (Actual /Theoretical) × 100

Percentage yield = (262.6 / 350.9) × 100

Percentage yield = 74.8%

Learn more about stoichiometry:

brainly.com/question/14735801

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