Reactants + Energy → Products. Note: ΔH represents the change in energy. In endothermic reactions, the temperature of the products is typically lower than the temperature of the reactants. ... The energy needed for the reaction to take place comes from the water, which gets colder as the reaction proceeds.
Answer : The mass of ethylene glycol is, 437.34 grams
Solution : Given,
Volume of ethylene glycol = 394 ml
Density of ethylene glycol = 1.11 g/ml (Standard value)
Formula used :

Now put all the given values in this formula, we get the mass of ethylene glycol.


Therefore, the mass of ethylene glycol is, 437.34 grams
<span>I think There should be a valanced state in every atom. (Valanced state means, 8 electrons in the outer most orbit) In case take a atom has 8 electrons in the outer orbit, so when bonding the two atom to form a molecule, there is a Ionic Bond (because of both atoms has its own valanced electron(8 electrons in outer most orbit).</span>
Answer:
The concentration of fructose-6-phosphate F6P ≅ 1.35 mM
Explanation:
Given that:
ΔG°′ is the conversion of glucose-6-phosphate to fructose-6-phosphate (F6P) = +1.67 kJ/mol = 1670 J/mol
concentration of glucose-6-phosphate at equilibrium = 2.65 mM
Assuming temperature = 25.0°C
=( 25 + 273)K
= 298 K
We are to find the concentration of fructose-6-phosphate
Using the relation;
ΔG' = -RT In K_c
where;
R = 8.314 J/K/mol
1670 = - (8.314 × 298 ) In K_c
1670 = -2477.572 × In K_c
1670/ 2477.572 = In K_c
0.67 = In K_c

0.511
Now using the equilibrium constant 
![K_c = \dfrac{[F6P]}{[G6P]}](https://tex.z-dn.net/?f=K_c%20%3D%20%5Cdfrac%7B%5BF6P%5D%7D%7B%5BG6P%5D%7D)
![0.511 = \dfrac{[F6P]}{[2.65]}](https://tex.z-dn.net/?f=0.511%20%3D%20%20%5Cdfrac%7B%5BF6P%5D%7D%7B%5B2.65%5D%7D)
F6P = 0.511 × 2.65
F6P = 1.35415
F6P ≅ 1.35 mM