1 mole of nitric acid produce 1 mole of ammonium nitrate.
moles in 5000 kg of ammonium nitrate :
( molecular mass of ammonium nitrate is 80 gm/mol )
So, number of moles of nitric acid required are also 62500 moles.
Mass of 62500 moles of nitric acid :
Hence, this is the required solution.
Answer:
Explanation:
Hello!
In this case, given the chemical reaction:
In such a way, given the volumes and molarities of each reactant, we can compute the moles of produced iron (III) hydroxide by each of them, via the 3:1 and 1:1 mole ratios:
It means that the sodium hydroxide is the limiting reactant and 0.00833 moles of iron (III) hydroxide are produced; thus, the required mass is:
While an electromagnetic wave<span> is called just a disturbance, a </span>mechanical wave<span> is considered a periodic disturbance. </span>Mechanical waves<span> are also called elastic </span>waves<span>as their propagation depends on the elastic properties of the medium through which the </span>waves<span> pass.</span>
Answer:
1455.6
Explanation: you first convert 2250ml to l by dividing by 1000 so you get 2.25l then you use Boyles law which is p1v1=p2v2 then insert values
35.75*100=p2*2.25 then divide both sides by 2.25 then you get 1455.6
Answer:
oof idk I would suggest looking at an example and try going off that
