The sum of my digits is equal to 5
1 answer:
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Answer:
y-4=7(x-1)
Step-by-step explanation:
Hi there!
We are given the slope of the line (7) and the point (1,4) and we need to find the equation in point-slope form.
Point-slope form is given as y-=m(x-
) where m is the slope and (
,
) is a point
We have all of the needed information for the equation, but let's first label the values of everything in order to avoid confusion
m=7
=1
=4
now substitute into the formula:
<u>y-4=7(x-1)</u>
Hope this helps! :)
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is