Answer:
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g)
Explanation:
All the following are oxidation–reduction reactions except:________
a. H₂(g) + F₂(g) → 2HF(g). Redox. H is oxidized and F is reduced.
b. Ca(s) + H₂(g) → CaH₂(s). Redox. Ca is oxidized and H is reduced.
c. 2K(s) + 2H₂O(l) → 2KOH(aq) + H₂(g). Redox. K is oxidized and H is reduced.
d. 6Li(s) + N₂(g) → 2Li₃N(s). Redox. Li is oxidized and N is reduced.
e. Mg₃N₂(s) + 6H₂O(l) → 3Mg(OH)₂(s) + 2NH₃(g). Not redox. All the elements have the same oxidation number
Answer:
0.02L
Explanation:
Using the formula V1/T1 = V2/T2
Given
V1 = 0.5L
T1 = 25 degrees
T2 = 1 degree
V2 =?
Substitute
0.5/25 = V2/1
Cross multiply
25V2 = 0.5
V2 = 0.5/25
V2 = 0.02L
Hence the new volume will be 0.02L
We assume that the volume of the molecules themselves in a gas sample is negligible compared to the bulk volume of the gas sample: this helps us to explain why gases are so compressible.
⇒ only atom consist of 1 electron and one proton
Rest atoms greater than 1 atomic number (neutral) have neutrons,electrons and protons.