Answer:
Q = 1.68 Kcal
Explanation:
∴ m H2O = 12.0 g
∴ T1 = 35°C ≅ 308 K
∴ T2 = 175°C ≅ 448 K
∴ ΔT = T2 - T1 = 175 - 35 = 140 °C
∴ Cp H2O = 1 cal /g.°C
⇒ Q = (12.0 g)(1 cal/g°C)(140 °C)
⇒ Q = (1680 cal)*(Kcal/1000 cal)
⇒ Q = 1.68 Kcal
The answer 1.60217662 x 10^-19<span />
When the amount of gas in a container is increased, the volume increases. Lussac's law states that the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature.
The rubbing creates a negative charge that is carried by electrons. The electrons can build up t produce static electricity.
Inquiry; wanting to know. Thinking critically to figure out, understand. However being skeptic to not fall on one simple answer. For possibly, it could be incorrect.
