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GrogVix [38]
3 years ago
10

In a strong acid–strong base titration (both monoprotic), if 25.0 milliliters of the base is required to completely neutralize 2

5.0 milliliters of the acid, which of the following conclusions can you make?
A)The concentartion of the acid is higher than that of the base.
B)The concentration of the acid is the same as that of the base.
C)The concentration of the base is higher than that of the acid.
D)The equivalence point will occur arround a pH of 2.5.
Chemistry
2 answers:
andrezito [222]3 years ago
6 0

The concentration of the acid is the same as that of the base.

If equal volumes of acid and base are required, you can conclude that the concentrations must be the same.

taurus [48]3 years ago
5 0
B)The concentration of the acid (C₁) is the same as that of the base (C₂).

V₁=V₂

n(acid)=C₁V₁
n(base)=C₂V₂

HX + YOH = YX + H₂O

n(acid)=n(base)

C₁V₁=C₂V₂

C₁=C₂
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while ionic compounds in the solid state do not conduct electricity, when they are melted, electric current
evablogger [386]

Answer:

Explanation:

Ionic (or electrovalent) compounds conduct electricity when there they are in the aqueous state/solution because the charges of ions of these compounds are what carry the electric charges in the aqueous solution as a result of free movement within the aqueous solution which they do not "have" when in there solid state (where they have a highly restricted movement/compacted structure).

3 0
2 years ago
Which statement is true in comparison to a weak acid, a strong acid
Allushta [10]

Answer: Strong acid vs weak acid

Strong acids and strong bases refer to species that completely dissociate to form ions in solution.

Explanation: By contrast, weak acids and bases ionize only partially, and the ionization reaction is reversible. Thus, weak acid and base solutions contain multiple charged and uncharged species in dynamic equilibrium.

7 0
2 years ago
PLEASE HELP MEEE!!!!
Assoli18 [71]
It would be 35.8 Calories or calories. Not sure about that part. Hope this helps though.
3 0
3 years ago
List the following bond types in order of increasing strength: non-polar covalent bonds, ionic bonds, hydrogen bonds, polar cova
ss7ja [257]

Answer: Option (B) is the correct answer.

Explanation:

  • An ionic bond is formed by the sharing of electrons between two chemically combining atoms.

In an ionic bond, there occurs attraction between oppositely charged ions due to which there occurs strong forces of attraction between them. Therefore, ionic bonds are the strongest bonds.

  • A polar covalent bond is formed due to unequal sharing of electrons between the combining atoms.

For example, H_{2}O is a polar covalent compound. Partial opposite charges tend to develop on the atoms of a polar covalent compound.

  • A non-polar covalent bond is formed due to equal sharing of electrons between the combining atoms.

For example, Cl_{2} is a non-polar covalent molecule. No partial charges will be there on the atoms of a non-polar covalent molecule.

  • A hydrogen bond is defined as the bond formed between a hydrogen atom and an electronegative atom.

For example, in HCl compound there occurs hydrogen bonding.

In this type of bond, dipole-dipole attractive interactions tend to take place. And, strength of hydrogen bonds is very weak.

Thus, we can conclude that given bond types are arranged in order of increasing strength as follows.

      Hydrogen bonds < non-polar covalent bonds < polar covalent bonds < ionic bonds

8 0
3 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
Dvinal [7]

Answer:

K(48.5°C) = 1.017 E-8 s-1

Explanation:

  • CH3Cl + H2O → CH3OH + HCl

at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

Arrhenius eq:

  • K(T) = A e∧(-Ea/RT)
  • Ln K = Ln(A) - [(Ea/R)(1/T)]

∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

⇒ Ln (K1/K2) = - 3.422

⇒ K1/K2 = e∧(-3.422)

⇒ (3.32 E-10 s-1)/K2 = 0.0326

⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
3 years ago
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