B.) acceleration.
hope this helps:)
Answer:
4.617 s
Explanation:
The speed of 60 mi/h can be converted to m/s:
(60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s
The relationship between speed and acceleration is ...
v = at
t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s
It will take the car 4.617 seconds to reach 60 mi/h starting from rest.
Both cars are canceling out the energy of each other. The energy that is left over because one car has a bigger kinetic energy is the energy that is going to move BOTH the cars.
First Car : <em>0.5 * 2000kg * 3m/s^2 = 10.24 KJ</em>
Second Car :<em> 0.5 * 2000kg * 2m/s^2 = 4 KJ</em>
Leftover Energy : <em>10.24 KJ - 4 KJ = 6.24 KJ
</em>
Movement of BOTH cars :<em /><em>
6.24 = 4000kg * v^2
</em>v = √(6.24 / 4000) =0.04 m/s = 4 cm/s
Answer:
(a)10.5 rad/s2
(b) 20.9 rev
(c) 47.27 m
Explanation:
As the block of mass 53 kg is falling and pulling on the rope. The tension force on the rope must be equal to the gravity acting on the block according to Newton's 3rd law
T = mg = 53*9.81 = 519.93 N
Since this tension force would rotate the cylinder freely without any friction. The torque created by this tension force is
To = TR = 519.93 * 0.36 = 187.17 Nm
This solid cylinder would have a moment of inertia around it's rotating axis of:
(a)We can use Newton's 2nd law to calculate the angular acceleration exerted by such torque on the solid cylinder
(b) With such constant angular acceleration, the angle it would make after 5s is
Since each revolution equals to 
of angle, we can calculate the number of revolution it makes
(c) Assume the thickness of the rope is negligible (and its wounded radius is unchanging), we can calculate the rope length unwinded after rotating 131.3rad
When two magnets are brought together, the opposite poles will attract one another, but the like poles will repel one another. This is similar to electric charges. Like charges repel, and unlike charges attract.
pls. mark brainliest am. dyning for it
