Answer:
9.0 L/min
Explanation:
From the given information, the flow rate in the wider section appears to four times that of the narrow section.
Since the flow rate for a pipe at any time (t) = Area (A) × speed (V)
we can say that:
Then, the flow rate in the wider section will also be 9.0 L/min. This is because the mass flow rate must be kept constant regardless of the changes in the size of the cross-sectional area.
The current in the circuit is 5 A
Explanation:
The intensity of current is given by the equation:
where
I is the current
q is the amount of charge passing through a given point of the circuit in a time interval of t
For the cell in this problem, we have
q = 150 C is the charge
t = 30 s is the time interval
Substituting into the equation, we f ind
Learn more about current:
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