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NikAS [45]
3 years ago
10

Speed training increases one's maximum velocity. a. True b. False

Physics
2 answers:
Harrizon [31]3 years ago
3 0
That is absolutely true.
docker41 [41]3 years ago
3 0
Yup! it's True.It's true
You might be interested in
A train moves from rest to a speed of 25 m/s in 30.0 seconds. What is the acceleration?
fredd [130]

Answer:

a = 0.83\ m/s^2

Explanation:

<u>Uniform Acceleration </u>

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

It's known a train moves from rest (vo=0) to a speed of vf=25 m/s in t=30 seconds. It's required to calculate the acceleration.

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

Substituting:

\displaystyle a=\frac{25-0}{30}

\boxed{a = 0.83\ m/s^2}

4 0
3 years ago
PLEASE HELP and actually help plz
frutty [35]

Answer:

iEvaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)Evaluate  for \(x=2.\)

Explanation:

3 0
3 years ago
An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?
ikadub [295]
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
7 0
3 years ago
A 34.0 kg sled is accelerated by a constant force of 45.0 N from 2.00 m/s to 16.00 m/s. For how long was the force acting on the
goblinko [34]

Answer: 10.6 sec

Explanation:

Because I got it right on my quiz :D

also because you can use the impulse momentum formula, Ft=m(triangle)v

so basically u do 16m/s-2m/s=14m/s and thats your triangle v (change in velocity) then multiply 14 times the mass, which is 34. Thats 476, so now you have ft=476, and you know F, the force, so all you have to do is divide 476 by 45, and you get like 10.5777777 which rounds up to 10.6!

4 0
3 years ago
Find the time taken if the speed of a train increased rom 72km/h to 90km/h for 234km
Katarina [22]

Answer:

2.89 hours

Explanation:

given :

Vo = 72 km/h

Vt = 90 km/h

S = 234 km

find : the time taken (t) = ?

solution :

2.a.s = Vt² - Vo²

2.a.(234) = 90²- 72²

468.a = 8100 - 5184

= 2916

a = 2916/468 = 6.23 km/h²

so,

t = (Vt-Vo) /a

= (90-72)/ 6.23

= 18/ 6.23

= 2.89 hours

7 0
3 years ago
Read 2 more answers
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