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Maru [420]
3 years ago
8

What information is needed to calculate the ph of a solution?

Chemistry
1 answer:
Nonamiya [84]3 years ago
6 0
The concentration of H+ or OH- ions.
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Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
What is the name of this formula?
Alex_Xolod [135]

Answer:

Iron(III) Oxide

Explanation:

You can tell that this formula is for the molecule Iron(III) oxide because it has two iron atoms and three oxygen atoms.

Fun Fact: There are three main types of iron oxides, with this being one of them.

Hope this helped! :^)

3 0
2 years ago
What do you call a mass of rock and soil deposited directly by <br> a glacier
melomori [17]
It's called a "Till"
6 0
3 years ago
An archaeologist graduate student found a leg bone of a large animal during the building of a new science building. The bone had
Vlad [161]

Answer : The time passed in years is 2.74\times 10^2\text{ years}

Explanation :

Half-life of carbon-14 = 5730 years

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{5730\text{ years}}

k=1.21\times 10^{-4}\text{ years}^{-1}

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}\text{ years}^{-1}

t = time passed by the sample  = ?

a = initial amount of the reactant disintegrate = 15.3

a - x = amount left after decay process = 14.8

Now put all the given values in above equation, we get

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{15.3}{14.8}

t=274.64\text{ years}=2.74\times 10^2\text{ years}

Therefore, the time passed in years is 2.74\times 10^2\text{ years}

4 0
3 years ago
What are all 18 groups of the periodic table?
lukranit [14]

Go to this website for any Periodic table help. It helped me so much!

https://www.chemicool.com/


6 0
3 years ago
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