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4 years ago

Write the balanced equation for the neutralization reaction between h2so4 and koh

Chemistry

1 answer:

Dafna11 [192]4 years ago

8 0

H2SO4 + 2KOH ---> K2SO4 + 2H2O
:)

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What is the reaction for CL^2 + 2 KBr —> 2 KCL+Br^2 of 11 grams of potassium bromide?

mylen [45]

Answer:

All the amounts of reactants and products are:

KBr

11.0g (given)

0.0924 mol

Cl₂

0.0462 mol

3.28g

KCl

0.0924 mol

6.89 g

Br₂

0.0462 mol

7.39 g

Explanation:

1. Balanced chemical equation (given)

$Cl_2+2KBr\rightarrow 2KCl+Br_2$

2. Mole ratios

$\dfrac{1molCl_2}{2molKBr}$

$\dfrac{2molKCl}{2molKBr}$

$\dfrac{1molBr_2}{2molKBr}$

3. Molar masses

Molar mass Cl₂: 70.906g/mol

Molar mass KBr: 119.002 g/mol

Molar mass KCl: 74.5513 g/mol

Molar mass KBr: 159.808 g/mol

4. Convert 11 grams of potassium bromide to moles:

#moles = mass in grams / molar mass

#mol KBr = 11g / 119.002g/mol = 0.092435mol KBr

5. Use the mole ratios to find the amounts of Cl₂, KCl, and Br₂

a) Cl₂

$\dfrac{1molCl_2}{2molKBr}\times 0.092435molKBr=0.0462molCl_2$

$0.0462175molCl_2\times 70.906g/molCl_2=3.28gCl_2$

b) KCl

$\dfrac{2molKCl}{2molKBr}\times0.092435molKBr=0.0924molKCl$

$0.092435molKCl\times 74.5513g/molKCl=6.89gKCl$

c) Br₂

$\dfrac{1molBr_2}{2molKBr}\times 0.092435molKBr=0.0462molBr_2$

$0.0462175molBr_2\times 159.808g/molBr_2=7.39gBr2$

The final calculations are rounded to 3 sginificant figures.

3 0

4 years ago

1. A gas has an initial volume of 13 L at a pressure of 1.8 atm. What will be the new pressure at a volume of 5 L?

adelina 88 [10]

Hey there!:

The law of boyle is used:

initial pressure ( P1 ) = ?

initial volume ( V1 ) = 13 L

final pressure ( P2 ) = 1.8 atm

final volme ( V2 ) = 5 L

P1 *V1 = P2 * V2

P1 * 13 = 1.8 * 5

P1 * 13 = 9

P1 = 9 / 13

P1 = 0.692 atm

Hope this helps!

5 0

3 years ago

Which element has the electronic configuration, 1s22s22p63s23p64s1 ?

Alinara [238K]

Answer:

Potassium element has the electronic configuration, 1s22s22p63s23p64s1.

3 0

3 years ago

You are on a field trip to a nearby lake for biology class and want to perform a quick analysis of the water’s approximate pH le

umka21 [38]

The easiest way to approximate ph level is the ph paper because there are no exprimentation required and it is very handy. so it is the best way to approximate the ph level of a lake, especially when you are outdoors, and it is just an initial reading of the ph. so ph paper will do.

4 0

3 years ago

Read 2 more answers

The reaction 2 H:O 2 H3 + O, would be correctly classified as a decomposition reaction (T/F)

sp2606 [1]

Answer:

Explanation:

It's false, but not because it is not a decomposition equation. It does resemble one.

As near as I can tell, it should be

2H2O >>> 2H2 + O2

8 0

3 years ago