We want:
S(s) + O2(g) --> SO2(g)
So the following are the given:
1) S(s) + 3/2O2(g) --> SO3(g) ∆H = -395.8 kJ/mole
2) 2SO2 + O2 --> 2SO3(g) ∆H = -198.2 kJ/mole
Reverse Equation 2) and then divide by 2
SO3(g) --> SO2(s) + 1/2O2(g) ∆H = +99.1 kJ/mole
Add Equation 1)
S(s) + O2(g) --> SO2(g) ∆H = -296.7 kJ/mole
Answer:
4.61 x 10^23
Explanation: Convert 213g of PbCl2 to mol, which is 0.7658950184462004, multiply 0.765 with 6.022 x 10^23.
To get the empirical formula of this compound, we take a basis of 100 grams which means each percentage is equivalent to 1 gram. Hence there is 32.39 grams sodium, 22. 53 grams sulfur and 45.07 grams oxygen. We convert each mass to their moles by dividing by their respective molar mass. Na: 1.408, S:0.704 and O:2.82. divide each with the lowest: Na: 2: S: 1 and O:4. Hence the formula is Na2SO4.
Answer:
c.
Explanation:
it moves in slow convection currents, hope this helps!
Either C or D. Those r the answers that make more sense.
