Answer:
6) λ = 0.84 × 10⁻⁸ m
7) λ = 0.84 × 10⁻⁶ m
Explanation:
6) Given data:
Wavelength of photon = ?
Frequency of photon = 3.56 × 10¹⁶ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 3.56 × 10¹⁶ Hz × λ
λ = 3×10⁸ m/s / 3.56 × 10¹⁶ s⁻¹
λ = 0.84 × 10⁻⁸ m
7) Given data:
Wavelength of photon = ?
Frequency of photon = 6.15 × 10¹⁴ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 6.15 × 10¹⁴ Hz × λ
λ = 3×10⁸ m/s / 6.15 × 10¹⁴ Hz s⁻¹
λ = 0.84 × 10⁻⁶ m
Change(A chemical reaction.)
Electron requires energy to move from ground state to excited state(higher energy levels). Hence option 1 is correct. Hope this helps!
Answer: C. Europa Clipper
Explanation:
The balanced combustion reaction for one mole of ethane will be
C2H6 + 3.5 O2 ---> 2CO2(g) + 3H2O (l)
Enthalpy of reaction of combustion = ∑ΔHf (products)- ∑ΔHf (reactant)
ΔHf = enthalpy of formation
The enthalpy of formation of oxygen = 0 as it is an element in its native state
ΔHf C2H6 = -83.820 kJ / mole
ΔHf H2O = -285.830 kJ / mole
ΔHf CO2 = -393.509 kJ / mole
ΔHrxn = [2 X ΔHf CO2 + 3 X ΔHf H2O] - [ΔHf C2H6]
ΔHrxn = [2 X (-393.509) + 3 (-285.830)] - [-83.820]
ΔHrxn = -1560.688 kJ / mole
