Answer : The number of moles of
form will be, 0.01360 moles
Solution : Given,
Mass of
= 3.58 g
Molar mass of
= 394.71 g/mole
Molar mass of
= 253.80 g/mole
First we to calculate the moles of moles of
.
![\text{Moles of }NI_3=\frac{\text{Mass of }NI_3}{\text{Molar mass of }NI_3}=\frac{3.58g}{394.71g/mole}=9.069\times 10^{-3}moles](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DNI_3%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DNI_3%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DNI_3%7D%3D%5Cfrac%7B3.58g%7D%7B394.71g%2Fmole%7D%3D9.069%5Ctimes%2010%5E%7B-3%7Dmoles)
Now we have to calculate the moles of
.
The balanced reaction is,
![2NI_3\rightarrow N_2+3I_2](https://tex.z-dn.net/?f=2NI_3%5Crightarrow%20N_2%2B3I_2)
From the balanced reaction, we conclude that
As, 2 moles of
gives 3 moles of ![I_2](https://tex.z-dn.net/?f=I_2)
So,
moles of
gives
moles of ![I_2](https://tex.z-dn.net/?f=I_2)
Therefore, the number of moles of
form will be, 0.01360 moles