Answer:

Given:

To find:

Step-by-step explanation:

Answer:
area of a triangle is 1/2×h×b
Step-by-step explanation:
1÷2×12×13
=78
The answer is zero, i think
P = 2(L + W)
P = 200
L = W + 80
200 = 2(W + 80 + W)
200 = 2(2W + 80)
200 = 4W + 160
200 - 160 = 4W
40 = 4W
40/4 = W
10 = W.........the width is 10 yds