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Sonbull [250]
2 years ago
10

Write down the formulas of the following compounds: magnesium chloride, alumina, chlorine (VII) oxide, sodium sulfide, calcium

oxide.
Chemistry
1 answer:
olasank [31]2 years ago
7 0

Answer:

- Magnesium chloride: MgCl₂.

- Alumina: Al₂O₃.

- Chlorine (VII) oxide: Cl₂O₇.

- Sodium sulfide: Na₂S.

- Calcium oxide: CaO.

Explanation:

Hello!

In this case, according to the naming rules for the given compounds, which state that binary salts have a metal and a nonmetal and oxides contain oxygen, we have:

- Magnesium chloride: MgCl₂.

- Alumina: Al₂O₃.

- Chlorine (VII) oxide: Cl₂O₇.

- Sodium sulfide: Na₂S.

- Calcium oxide: CaO.

Best regards!

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Whose work directly resulted in the development of an atomic model that has negative electrons stuck within a sea of positive ma
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Explanation: It verified J. J. Thomson's work on the atomic structure.

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1‑Propanol ( P⁰ 1 = 20.9 Torr at 25 ⁰C ) and 2‑propanol ( P⁰ 2 = 45.2 Torr at 25 ⁰C ) form ideal solutions in all proportions. L
anastassius [24]

Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

Explanation : Given,

Vapor presume of 1‑Propanol (P^o_1) = 20.9 torr

Vapor presume of 2‑Propanol (P^o_2) = 45.2 torr

Mole fraction of 1‑Propanol (x_1) = 0.540

Mole fraction of 2‑Propanol (x_2) = 1-0.540 = 0.46

First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.

p_1=x_1\times p^o_1

where,

p_1 = partial vapor pressure of 1‑Propanol

p^o_1 = vapor pressure of pure substance 1‑Propanol

x_1 = mole fraction of 1‑Propanol

p_1=(0.540)\times (20.9torr)=11.3torr

and,

p_2=x_2\times p^o_2

where,

p_2 = partial vapor pressure of 2‑Propanol

p^o_2 = vapor pressure of pure substance 2‑Propanol

x_2 = mole fraction of 2‑Propanol

p_2=(0.46)\times (45.2torr)=20.8torr

Thus, total pressure = 11.3 + 20.8 = 32.1 torr

Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.

\text{Mole fraction of 1-Propanol}=\frac{\text{Partial pressure of 1-Propanol}}{\text{Total pressure}}=\frac{11.3}{32.1}=0.352

and,

\text{Mole fraction of 2-Propanol}=\frac{\text{Partial pressure of 2-Propanol}}{\text{Total pressure}}=\frac{20.8}{32.1}=0.648

Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

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the right answer is 9110

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djyliett [7]

Explanation:

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The periodic table can be divided into four blocks based on the type of sublevels their valence electrons occupy.

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Learn more:

Periodic table brainly.com/question/2014634

#learnwithBrainly

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