Ask question

Ask question

All categories

2 years ago

10

Write down the formulas of the following compounds: magnesium chloride, alumina, chlorine (VII) oxide, sodium sulfide, calcium

oxide.

1 answer:

olasank [31]2 years ago

7 0

Answer:

- Magnesium chloride: MgCl₂.

- Alumina: Al₂O₃.

- Chlorine (VII) oxide: Cl₂O₇.

- Sodium sulfide: Na₂S.

- Calcium oxide: CaO.

Explanation:

Hello!

In this case, according to the naming rules for the given compounds, which state that binary salts have a metal and a nonmetal and oxides contain oxygen, we have:

- Magnesium chloride: MgCl₂.

- Alumina: Al₂O₃.

- Chlorine (VII) oxide: Cl₂O₇.

- Sodium sulfide: Na₂S.

- Calcium oxide: CaO.

Best regards!

You might be interested in

Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?

LenKa [72]

The volume could be calculated by using <span>V = n RT / P </span>

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure

I believe the answer is

<span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa

</span>

6 0

3 years ago

Is the osmotic pressure of a 0.10 M solution of NaCl greater than, less than, or equal to that of a 0.10 M solution of KBr?a. eq

jonny [76]

Answer:

a. equal to

Explanation:

The <em>osmotic pressure</em> is calculated by the formula:

π = <em>i</em> * M * R * T

Where π is the osmotic pressure, M is the concentration, R is a constant, T is temperature and <em>i</em> is the van't Hoff's factor (the number of ions a compound forms when dissolved in water,<u> for both NaCl and KBr is 2</u>).

Because R is always the same, and <u>Temperature and Concentration are equal between the two solutions</u>, the osmotic pressure of both solutions are also equal.

4 0

3 years ago

How many molecules would be in 2.5 moles of H2O.show work

Fantom [35]

Answer:

1.5x 10^24

Explanation:

for every 1 mol there are 6.02 x 10^23 molecules

2.5 mol x 6.02 x 10^23

-----------------

1 mol

5 0

2 years ago

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 6 days

a = initial amount of the reactant = 1 g

a - x = amount left after decay process = 0.2 g

a) to find the rate constant

$6=\frac{2.303}{k}\log\frac{1.0}{0.2}$

$k=\frac{2.303}{6}\log\frac{1.0}{0.2}$

$k=0.268days^{-1}$

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days$

The half life is 2.58 days

3 0

2 years ago

How many formula units are there in 450 g of Na2S04?

Mashutka [201]

Formula units in 450 g of $Na_{2} So_{4}$ is 1.93 × 10²⁴ formula units.

<u>Explanation:</u>

First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,

$$\frac{450 g}{142.04 g/mol} = 3.2 moles$

Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.

3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.

So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.

4 0

2 years ago