It's being planned to launch in the 2020's
Answer:
The linear charge density is 5.19 X 10⁻⁶ C/m
Explanation:
The potential difference between two cylinders, is given as
V = (λ/2πε)ln(b/a)
where;
λ is the line charge density on the power line.
b is the distance between the power line = 1 m
a is the radius of the wire = 1.5 cm = 0.015 m
ε is the permittivity of free space = 8.9 X 10⁻¹² C
V*2πε = λ* ln(b/a)
3900 *(2π*8.9 x10⁻¹²)= λ *ln(1/0.015)
2.1812 X 10⁻⁷ = 4.1997* λ
λ = 5.19 X 10⁻⁶ C/m
Therefore, the linear charge density is 5.19 X 10⁻⁶ C/m
Answer:
following are the solution to this question:
Explanation:
When I stand at such a scale in an elevated that's already rising upwards, its scale would appear to also be 0 because of free fall and would often reveal that weight whenever the lift is stable.
In this, the free fall is also known as the object, that is influenced exclusively by gravity, and an object operating only through the influence of gravity is said to be in a free-fall state.
(a) The lowest frequency (called fundamental frequency) of a wire stretched under a tension T is given by

where
L is the wire length
T is the tension
m is the wire mass
In our problem, L=10.9 m, m=55.8 g=0.0558 kg and T=253 N, therefore the fundamental frequency of the wire is

b) The frequency of the nth-harmonic for a standing wave in a wire is given by

where n is the order of the harmonic and f1 is the fundamental frequency. If we use n=2, we find the second lowest frequency of the wire:

c) Similarly, the third lowest frequency (third harmonic) is given by