Answer:
For metal it's Malleable. For non metal is not ductile, on the right side, and poor conductor of heat and electricity. For metalloid it is in between metals and non metals, and semi conductor of heat and electricity
Answer:
F = 0.414 N
Explanation:
Given that,
Magnetic flux density,
The length of the wire, l = 24 m
Current, I = 0.48 A
We need to find the force acting on the wire. The formula for the force is given by:

Put all the values,

So, the force acting on the copper wire is equal to 0.414 N.
Habitat
-In the Sonoran Desert region, elf owls are found mainly in riparian habitats (places where there is water), or in areas where saguaro cactus are plentiful.
Range
-Elf Owls are found from the southwest USA to Central Mexico and Baja California. Northern populations winter in Central Mexico and on the Pacific slope north to Sinaloa, Mexico.
Wild Status
-The most important threat to the elf owl is habitat loss both of its riparian forest habitat and desert-scrub habitats. In Arizona, the elf owl is not uncommon, but it's numbers are decreasing in California and Texas.
-So I mean like ya it's possible that they could live in cacti. Sorry that I couldn't give you a straight answer.
couldlive in
Answer:
h = 3.10 m
Explanation:
As we know that after each bounce it will lose its 11% of energy
So remaining energy after each bounce is 89%
so let say its initial energy is E
so after first bounce the energy is

after 2nd bounce the energy is

After third bounce the energy is

here initial energy is given as

now let say final height is "h" so after third bounce the energy is given as

now from above equation we have




Answer:
1.8m
Explanation:
Let the Elastics of the steel ASTM-36 
The strain of the bar when subjected to 150 MPa is

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

or 1.8m