Use photomath it is a really good app u should try it
so, is a semi-circle, half a circle, recall a circle has a total of 360°, so half of that will be 180°.
the diameter of that circle is 10, so its radius is half that, or 5.
![\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ \theta =180\\ r=5 \end{cases}\implies s=\cfrac{(180)(\pi )(5)}{180}\implies s=5\pi \stackrel{\pi =3.14}{\implies s=15.7}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barc%27s%20length%7D%5C%5C%5C%5C%20s%3D%5Ccfrac%7B%5Ctheta%20%5Cpi%20r%7D%7B180%7D~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20%5Ctheta%20%3Dangle~in%5C%5C%20%5Cqquad%20degrees%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20%5Ctheta%20%3D180%5C%5C%20r%3D5%20%5Cend%7Bcases%7D%5Cimplies%20s%3D%5Ccfrac%7B%28180%29%28%5Cpi%20%29%285%29%7D%7B180%7D%5Cimplies%20s%3D5%5Cpi%20%5Cstackrel%7B%5Cpi%20%3D3.14%7D%7B%5Cimplies%20s%3D15.7%7D)
Answer:
i need more context-
Step-by-step explanation:
-11x² + 2x = 10
-11x² + 2x - 10 = 10 - 10
-11x² + 2x - 10 = 0
x = <u>-(2) +/- √((2)² - 4(-11)(-10))</u>
2(-11)
x = <u>-2 +/- √(4 - 440)</u>
-22
x = <u>-2 +/- √(-436)
</u> -22<u>
</u>x = <u>-2 +/- 2i√(109)
</u> -22
x = <u>-2 + 2i√(109</u>) x = <u>-2 - 2i√(109)</u>
-22 -22
x = ¹/₁₁ - ¹/₁₁i√(109) x = ¹/₁₁ + ¹/₁₁i√(109)
<u />
Answer:
90 mins, or 1 hr and 30 mins. 3/2 hours, which would simplify to 1 1/2?
Step-by-step explanation:
