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olganol [36]
3 years ago
9

Please be my friend. my best and only friend isn't talking to me for some reason

Computers and Technology
2 answers:
Masja [62]3 years ago
5 0

Answer:

Oh no, why? thats wierd

marta [7]3 years ago
3 0
Everyone you meet in your life time your not gonna see them in the future you are gonna lose people in your life and friends is one of them
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What allow you to write alphas on a computer keyboard
lions [1.4K]

Answer:

"To create any of these Greek letters using the Alt codes, simply press the "Alt" key while simultaneously typing the listed number. For example, to create the Greek letter Alpha (α), press the "Alt" key and type 224 using the keypad at the right side of your keyboard." - GOOGLE

5 0
3 years ago
List out two ways to execute the script.​
castortr0y [4]

Answer:

1) Execute Shell Script Using File Name. Use the shell script file name to execute it either by using it's relative path or absolute path as shown below

2) Execute Shell Script Using Source Command.

7 0
3 years ago
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Which describes the third step in visual character development
allsm [11]

I would say 3-D model!!!! not 100% sure but this sounds most correct!

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3 years ago
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Because filling a pool/pond with water requires much more water than normal usage, your local city charges a special rate of $0.
nevsk [136]

Answer:

In C:

#include <stdio.h>

int main(){

   float length, width, depth,poolvolume,watervolume,charges;

   printf("Length (feet) : ");    scanf("%f",&length);

   printf("Width (feet) : ");    scanf("%f",&width);

   printf("Depth (feet) : ");    scanf("%f",&depth);

   poolvolume = length * width* depth;

   watervolume = length * width* (12 * depth - 3)/12;

   charges = 100 + 0.77 * watervolume;

   printf("Invoice");

   printf("\nVolume of the pool: %.2f",poolvolume);

   printf("\nAmount of the water needed: %.2f",watervolume);

   printf("\nCost: $%.2f",charges);

   printf("\nLength: %.2f",length);

   printf("\nWidth: %.2f",width);

   printf("\nDepth: %.2f",depth);

   printf("\nMr. Royal [Replace with your name] ");

   return 0;}

Explanation:

This declares the pool dimensions, the pool volume, the water volume and the charges as float    

float length, width, depth,poolvolume,watervolume,charges;

This gets input for length

   printf("Length (feet) : ");    scanf("%f",&length);

This gets input for width

   printf("Width (feet) : ");    scanf("%f",&width);

This gets input for depth

   printf("Depth (feet) : ");    scanf("%f",&depth);

This calculates the pool volume

   poolvolume = length * width* depth;

This calculates the amount of water needed

   watervolume = length * width* (12 * depth - 3)/12;

This calculates the charges

   charges = 100 + 0.77 * watervolume;

This prints the heading Invoice

printf("Invoice");

This prints the volume of the pool

   printf("\nVolume of the pool: %.2f",poolvolume);

This prints the amount of water needed

   printf("\nAmount of the water needed: %.2f",watervolume);

This prints the total charges

   printf("\nCost: $%.2f",charges);

This prints the inputted length

   printf("\nLength: %.2f",length);

This prints the inputted width

   printf("\nWidth: %.2f",width);

This prints the inputted depth

   printf("\nDepth: %.2f",depth);

This prints the name of the programmer

   printf("\nMr. Royal [Replace with your name] ");

   return 0;}

<em>See attachment for program in text file</em>

Download txt
3 0
3 years ago
Recursively computing the sum of the first n positive odd integers, cont. About (a) Use induction to prove that your algorithm t
julia-pushkina [17]

The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.

int recursiveOddSum(int n) {

 if(2n-1==1) return 1;

 return (2n-1) + recursiveOddSum(n-1);

}

To prove the correctness of this algorithm by induction, we start from the base case as usual:

f(1)=1

by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).

Now we can assume that f(n-1) returns indeed the sum of the first n-1 odd numbers, and we have to proof that f(n) returns the sum of the first n odd numbers. By the recursive logic, we have

f(n)=f(n-1)+2n-1

and by induction, f(n-1) is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, f(n) is the sum of the first n odd numbers, as required:

f(n)=\underbrace{\underbrace{f(n-1)}_{\text{sum of the first n-1 odds}}+\underbrace{2n-1}_{\text{n-th odd}}}_{\text{sum of the first n odds.}}

6 0
3 years ago
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