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2 years ago

HELP ME FIND THE PRODUCT

Mathematics

1 answer:

Brrunno [24]2 years ago

3 0

The product is 1.786e+25

You multiply in the paranthesis on both and then you mulitpoy them together

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Help me with area, please.

nikdorinn [45]

Answer:

Num. 2: A = 25, Num. 3 = 63, Num. 4 = 80

Step-by-step explanation:

I'll help with as many as I can, so a few of them I won't be able too answer. You should re-post those later. Good luck, hope this helps.

For number 2:

First, turn the triangle into a rectangle by cutting it in half and attaching it to the other half so it forms a rectangle.

Since you cut the triangle in half, you also have to split 5 in half, so the bottom length is now 2.5.

Now, simply multiply 2.5 by 10, and you have the area for number 2.

The area for number 2 is 25.

For number 3:

This one is much easier. Just think of the shape as a normal square that has been tipped to the side. That means that you would solve for area the same way: 9 x 7, which means that the area for number 3 is 63.

For number 4:

This one is also easy. Simply cut, and paste. Now the right side is 10, and the top side is 8. Multiply, and the area will be 80 m.

Please re-post 1 and 5, as I am not able to solve them. Sorry this answer took so long!

4 0

2 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

$m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}$

7 0

2 years ago

Find the product: (-8)(-6) =

larisa86 [58]

Answer:

48, since the numbers are next to each other with no sign, they need to be multiplied, and a negative times a negative is a positive

Step-by-step explanation:

hope this helps

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3 years ago

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3 years ago

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