Answer:
0.260 Celsius
Explanation:
q =c x m x (T2-T1)
c - specific heat of water 4.186 J/g.C
T2-T1 = q /(c x m) = 0.959 /(4.186 x 0.88) = 0.959/3.68 =0.260 C
Answer: -
37.5 g of NaCl are in 250 g of a 15.0% (by weight) solution.
Explanation: -
Total mass = 250 g
Percentage of NaCl = 15.0 %
=
Thus =
Number of grams of NaCl present =
= 37.5 g
One atom
33.7
i just know i had a question on it'
A. Sedimentry rock
b. high pressure
true.
Hope this helps!