Al and Bob are arguing about their algorithms. Al claims his O(nlogn)- time method is always faster than Bob's O(n^2 )- time met
1 answer:
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Explanation:
where,
= energy of
orbit
n = number of orbit
Z = atomic number
a) Energy change due to transition from n = 1 to n = ∞ ,hydrogen atom .
Z = 1
Energy of n = 1 in an hydrogen like atom:
Energy of n = ∞ in an hydrogen like atom:
Let energy change be E for 1 atom.
Energy for 1 mole = E'
The energy required to remove the electron in the ground state is 1,312.17 kJ/mol.
b) Energy change due to transition from n = 1 to n = ∞ , atom .
Z = 5
Energy of n = 1 in an hydrogen like atom:
Energy of n = ∞ in an hydrogen like atom:
Let energy change be E.
Energy for 1 mole = E'
The energy required to remove the electron in the ground state is 32,804.31 kJ/mol.
c) Energy change due to transition from n = 1 to n = ∞ ,atom .
Z = 3
Energy of n = 1 in an hydrogen like atom:
Energy of n = ∞ in an hydrogen like atom:
Let energy change be E.
Energy for 1 mole = E'
The energy required to remove the electron in the ground state is 11,809.55 kJ/mol.
d) Energy change due to transition from n = 1 to n = ∞ ,atom .
Z = 25
Energy of n = 1 in an hydrogen like atom:
Energy of n = ∞ in an hydrogen like atom:
Let energy change be E.
Energy for 1 mole = E'
The energy required to remove the electron in the ground state is 820,107.88 kJ/mol.